这样做的缺点/优点是什么:
define(function(require) {
var $ = require('jquery'), Backbone = require('backbone'), $content = $("#content");
return Backbone.Router.extend({
routes: {
"": "home",
"employees/:id": "employee"
},
home: function() {
require(["app/views/Home"], function (HomeView) {
var view = new HomeView({el: $content});
view.render();
});
},
employee: function(id) {
require(["app/views/Employee", "app/models/Employee"], function (EmployeeView, Employee) {
var employee = new Employee({id: id});
employee.fetch({
success: function (data) {
var view = new EmployeeView({model: data, el: $content});
view.render();
}
});
});
}
});
});
对此:
(注意第4-6行)
define(function(require) {
var $ = require('jquery'), Backbone = require('backbone'), $content = $("#content");
var HomeView = require("app/views/Home"),
EmployeeView = require("app/views/Employee"),
Employee = require("app/models/Employee");
return Backbone.Router.extend({
routes: {
"": "home",
"employees/:id": "employee"
},
home: function() {
var view = new HomeView({el: $content});
view.render();
},
employee: function(id) {
var employee = new Employee({id: id});
employee.fetch({
success: function (data) {
var view = new EmployeeView({model: data, el: $content});
view.render();
}
});
}
});
});
最佳答案
选项2会在应用程序启动时将所有依赖项加载到内存中(无论是否使用);选项 1 将在调用路由并且需要模块时动态加载依赖项。
我觉得选项 1 更好。
关于javascript - 在路由器 Action 中加载组件与路由器初始化之前加载组件的优缺点,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21651052/