主页是index.php，它包含一个不同的sidebar_signin_block.php文件，该文件创建用户登录 block 。在 sidebar_signin_block.php 中，如果登录成功，我将使用此 javascript 将它们发送到登录成功启动页面:echo "<script>window.open('login-success.php','_self')</script>";}现在，另一方面，如果登录失败，我有一个带有 javascript 的 else 语句，用于警告框，如下所示:echo "<script>alert('Email or password is incorrect please try again')</script>";
这是我的问题，需要帮助。在 index.php 页面上，如果登录成功或失败，包含的文件 sidebar_signin_block.php 将打开，并且是 View 中的网页。我想留在主页index.php并且不希望打开sidebar_signin_block.php页面。任何建议将不胜感激。
以防万一您需要它来诊断，我在下面包含了整个 sidebar-signin-block.php 文件:
<?php
session_start();
?>
<html>
<body>
<form method="post" action="sidebar-signin-block.php">
<table width="90%" border="0" align="center" bgcolor="white">
<tr>
<td bgcolor="ffffff" colspan="2" align="center"><h2>User Login</h2></td>
</tr>
<tr>
<td align="right">Email:</td>
<td><input type="text" name="email"></td>
</tr>
<tr>
<td align="right">Password:</td>
<td><input type="password" name="password"></td>
</tr>
<tr>
<td colspan="2" align="center"><input type="submit" name="login" value="Login"></td>
</tr>
<tr>
<td colspan="2" align="center"><h3 style="margin-top:7px;"><a href="nonadmin_user_forgot_password.php" target="_blank" title="Reset Your Lost Password">Forgot Password?</a></h3></td>
</tr>
<tr>
<td bgcolor="#ffffff" colspan="2" align="center"><div style="padding-top:5px;"><span style="font-size:20px;">Don't have an account?<br /><a href="/includes/register-user.php" title="Register with us!" target="_self">Sign Up</a> is <em>quick</em> and <em>easy</em>!</span></div></td>
</table>
</form>
<?php
// Connecting to the database and making the Bcrypt functions available
include("admin/includes/connect.php");
include ("lib/password.php");
// Gathering and sanitizing user login input
if(isset($_POST['login'])){
$email = trim(((isset($conn) && is_object($conn)) ? mysqli_real_escape_string($conn, $_POST['email']) :((trigger_error ("[MySQLConverterToo] Fix the mysql_escape_string() call! This code does not work.", E_USER_ERROR)) ? "" : "")));
$pass = trim(((isset($conn) && is_object($conn)) ? mysqli_real_escape_string($conn, $_POST['password']) : ((trigger_error ("[MySQLConverterToo] Fix the mysql_escape_string() call! This code does not work.", E_USER_ERROR)) ? "" : "")));
// Checking the database records for the user login input
$hash_query = "select nonadmin_user_pass from nonadmin_user_login where email='$email'";{
$run_query = mysqli_query($conn, $hash_query);}
while ($row = mysqli_fetch_assoc($run_query)) {
$fetch_pass = $row['nonadmin_user_pass'];
}
// If the user email and password matches we start a session
if ((password_verify($pass, $fetch_pass)) == 1){
// Verifying user login success with splash page then sending user back to the home page
$_SESSION['email']=$email;
echo "<script>window.open('login-success.php','_self')</script>";}
// When the user login fails an alert is given to inform them
else {
echo "<script>alert('Email or password is incorrect please try again')</script>";
echo "<script>window.open('index.php','_self')</script>";}
}
?>
</body>
</html>
最佳答案
登录表单的目标(action 属性)指向侧边栏文件。因此，当用户按下提交按钮时，浏览器会请求该页面并将其加载到当前框架中。
要避免这种情况，请向表单添加一个 submit 事件处理程序，该处理程序使用 AJAX 将表单数据发送到服务器，然后返回 false。这会抑制加载表单目标的正常浏览器行为。 AJAX 响应应指示登录是成功还是失败，此时您可以根据需要加载启动页面或显示警报。
关于Javascript 警报正在打开 PHP 包含文件并且不停留在主页上，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/29001415/