javascript - 多个数组对象操作

Question

array1 = [{"name":"John"},{"name":"James"}];
array2 = [{"gred_id":1,"name":"John","gred":"A"},{"gred_id":2,"name":"James","gred":"B"}];

我有 2 个像上面这样的数组。通过比较候选人的姓名，我想将 gred_id 放入 array1 中。我被困在这里了

$.each(array1,function(){
    var name= this["name"];

    $.each(array2, function(){
        if(name == this.name){
            this["grey_id"] = {"grey_id":this.id}; // not sure this is correct or wrong
        }
    });
});

这就是我最终想要的:

array1 = [{"name":"John","gred_id":1},{"name":"James","gred_id":2}];

Answer 1

根据 jQuery 的 .each() documentaion ，您不需要将该项存储在变量中。您可以使用 .each() 函数参数。第一个参数返回索引，第二个参数返回项目。

因此，您可以像这样优化代码。

Fiddle

var array1 = [{"name":"John"},{"name":"James"}];
var array2 = [{"gred_id":1,"name":"John","gred":"A"},{"gred_id":2,"name":"James","gred":"B"}];

$.each(array1, function (i, item) {
    $.each(array2, function (j, val) {
        if (item.name === val.name) {
            item.grey_id = val.gred_id;     
        }
    });
});

输出

array1 = [{"name":"John","gred_id":1},{"name":"James","gred_id":2}];