JavaScript - 打开、刷新和访问新选项卡

Question

我正在制作一个机器人来执行我从 Chrome 控制台运行的操作。它应该打开某个链接的新选项卡，然后在运行期间刷新它。每次刷新后，它应该使用 .getElementById 来查找某些内容，如果找到它(它是一个超链接)，它应该在新选项卡中打开它链接的位置。这是我到目前为止所得到的(充满错误，抱歉)。

var go = true;
var win = window.open("http://www.roblox.com/User.aspx?id=1211749", "_blank");
//WIN IS NULL FOR SOME REASON
function doTheThing()
{
    //BECAUSE WIN IS NULL, NOT SURE IF WORKS
    win.location.reload();
    //BECAUSE WIN IS NULL, NOT SURE IF WORKS
    //MUST GRAB ELEMENT FROM THE OTHER REFRESHED WINDOW
    var x = win.document.getElementById("ctl00_cphRoblox_rbxUserAssetsPane_UserAssetsDataList_ctl00_AssetNameHyperLink");
    var n = x.search("Federation");
    //If the link title has "Federation" in it
    if (n > -1 && go == true)
    {
        var win = window.open(x, '_blank');
        //MAY NOT WORK SINCE THE OTHER WINDOW.OPEN DOES NOT WORK
        //Open the window
        if(win)
        {
            win.focus();
        //go to it
        }
        go = false;
        //Keep it from opening 1000 windows
    }
}
while (go == true)
{
    var zhuLi = setInterval(doTheThing, 1000);
}

Answer 1

我想你想使用setInterval(...)函数，而不是 setTimeOut(...)。如果您想退出 setInterval 循环，可以使用 clearInterval() .