请大家帮忙。
在 Ajax 调用之后,我有一个包含两行(用户)的 JSON 对象。我有动态 ID,因为我打算在页面上加载一些内容(用于编辑用户详细信息的表单)。我的问题是 FOR 循环生成的每个用户行都具有相同的 ID。因此,所有 Ajax 生成的行都具有相同的 ID,在本例中为 48。 这是代码..
// Get the admin information
var loadAdmin = function() {
$.ajax({
type: 'GET',
id: id,
cache: false,
url: 'scripts/administratorsList.php?id=' + id
}).done(function(data) {
var adminData = JSON.parse(data);
for (var i in adminData) {
var userId = adminData[i].id;
$('#adminList').append('<li class="media"><a href="#" class="media-link" id="edit' + userId + '"><div class="media-left"><img src="assets/images/placeholder.jpg" class="img-circle" alt=""></div><div class="media-body"><div class="media-heading text-semibold">' + adminData[i].userName + '</div><span class="text-muted">Administrator</span></div><div class="media-right media-middle text-nowrap"><span class="text-muted"><i class="icon-pin-alt text-size-base"></i> ' + adminData[i].userCompany + '</span></div></a></li>')
// Add the edit form view here
$('#edit' + userId).on('click', function(userId) {
var userId = adminData[i].id;
$('#userConfig').append('Here I will generate the form to edit user ' + userId); // This is where the ID stays the same. I have used .append over .html for debugging purposes. Each row returns an ID of 48
});
}
});
};
下面是 JSON 文件
[{
"id": "17",
"userName": "Mark Bell",
"userCompany": "Pro Movers",
"userTelephone": "12345678911",
"userEmail": "info@info.uk",
"userPassword": "md5hash",
"userUAC": "6",
"originalUAC": "6",
"userRegistered": "20150826",
"activationKey": "0",
"userLastLoggedIn": "20160302",
"userBranch": "0",
"userAdmin": "0"
}, {
"id": "48",
"userName": "demo",
"userCompany": "Monstermove",
"userTelephone": "12345678912",
"userEmail": "info@info.uk",
"userPassword": "demo",
"userUAC": "6",
"originalUAC": "6",
"userRegistered": "20160305",
"activationKey": "0",
"userLastLoggedIn": "20160305",
"userBranch": "3",
"userAdmin": "3"
}]
提前致谢
通过 Jacub 的实现
for(adminData 中的 var i) {
var userId = adminData[i].id;
storeValueToRemainSame(userId);
}
function storeValueToRemainSame(userId) {
$('#adminList').append('<li class="media"><a href="#" class="media-link" id="edit' + userId + '"><div class="media-left"><img src="assets/images/placeholder.jpg" class="img-circle" alt=""></div><div class="media-body"><div class="media-heading text-semibold">' + adminData[i].userName + '</div><span class="text-muted">Administrator</span></div><div class="media-right media-middle text-nowrap"><span class="text-muted"><i class="icon-pin-alt text-size-base"></i> ' + adminData[i].userCompany + '</span></div></a></li>')
// Add the edit form view here
$('#edit' + userId).on('click', function(userId) {
var userId = adminData[i].id;
$('#userConfig').append('Here I will generate the form to edit user ' + userId); // This is where the ID stays the same. I have used .append over .html for debugging purposes. Each row returns an ID of 48
});
}
最佳答案
这里的问题是您引用了处理程序外部发生变化的值,因此保留了最后一个值。
for(var i in data) {
var value = i;
$('#someId').on('click', function(){
console.log(value);
});
}
唯一写入的值将是最后一个值,因为对其的引用将保留。 可能的解决方案例如:
function storeValueAndHandleClickEvent(value){
$('#someId').on('click', function(){
console.log(value);
});
}
for(var i in data) {
storeValueAndHandleClickEvent(i);
}
编辑:如果我使用与问题中相同的代码
for (var i in adminData) {
var userId = adminData[i].id;
storeValueToRemainSame(userId);
}
function storeValueToRemainSame(userId) {
$('#adminList').append('<li class="media"><a href="#" class="media-link" id="edit' + userId + '"><div class="media-left"><img src="assets/images/placeholder.jpg" class="img-circle" alt=""></div><div class="media-body"><div class="media-heading text-semibold">' + adminData[i].userName + '</div><span class="text-muted">Administrator</span></div><div class="media-right media-middle text-nowrap"><span class="text-muted"><i class="icon-pin-alt text-size-base"></i> ' + adminData[i].userCompany + '</span></div></a></li>')
// Add the edit form view here
$('#edit' + userId).on('click', function(userId) {
var userId = adminData[i].id;
$('#userConfig').append('Here I will generate the form to edit user ' + userId); // This is where the ID stays the same. I have used .append over .html for debugging purposes. Each row returns an ID of 48
});
}
关于javascript - 在 jquery 中迭代 json,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35916443/