Ajax jquery总是运行错误函数，尽管成功函数运行并且我可以获取 session 值，但我无法运行window.location="profile.php";
$(document).ready(function(){
$("#login").click(function(){
var username=$("#usern").val();
var password=$("#user").val();
$.ajax({
type: "POST",
url: "model/user.php",
data: {
user_log : username,
password : password
},
dataType: 'json',
error: function (xhr,textStatus,errorThrown) {
$("#error").html("<span style='color:#cc0000'>Error:</span> Invalid username and password. ");
},
success: function(json){
window.location="profile.php";
},
beforeSend:function()
{
$("#error").html("<img src='http://www.chinesecio.com/templates/base/images/loading.gif' /> Loading...")
}
});
return false;
});
});
用户.php
<?php
ob_start();
session_start();
error_reporting(E_ALL & ~E_NOTICE & ~E_DEPRECATED);
require_once(dirname(__FILE__).'/../model/connect.php');
?>
<?php
global $pdo;
if(isset($_POST['user_log'])) {
// username and password sent from Form
$username=$_POST['user_log'];
$password=$_POST['password'];
$qr= "SELECT * FROM user where username='$username' AND password='$password'" ;
$stmt= $pdo->query($qr);
$row= $stmt->fetch(PDO::FETCH_ASSOC);
if($stmt->rowCount() > 0)
{
$_SESSION['id']=$row['id'];
$_SESSION['name_mem']=$row['username'];
$_SESSION['level_mem']=$row['level'];
}
header("location:../../../../index.php");
}
?>
最佳答案
删除此行:
header("location:../../../../index.php");
如果上述不起作用，请从 ajax 属性中忽略此内容:
dataType: 'json',
关于javascript - ajax jquery 总是运行错误；，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/35981346/