javascript - javascript中的递归函数不返回标签

Question

我正在尝试返回标签匹配项，但我似乎在这里做错了什么。有人可以把我推向正确的方向吗？

console.log('start');

var test = {
    "ID": 234324,
    "Label": "KDF",
    "children": [{
        "ID": 234234,
        "Label": "KJDF",
        "children": [{
            "ID": 234324,
            "Label": "KJDF"
        }, {
            "ID": 22323,
            "Label": "LKNDF"
        }, {
            "ID": 34535,
            "Label": "LKNSF"
        }]
    }, {
        "ID": 323434,
        "Label": "CLK"
    }]
}

function testThis(thing, ID) {
    if (thing.ID == ID) {
        console.log('match!')
        return thing.Label;
    } else if (thing.children && thing.children.length) {
        thing.children.forEach(function(x) {
            console.log(x);
            return testThis(x, ID);
        })
        return false;
    } else {
        return false;
    }



}




console.log(testThis(test, 323434));

console.log('end');

Answer 1

你在哪里

thing.children.forEach(function(x) {

使用.some()而不是 .forEach()，像这样

return thing.children.some(function(x) {})

.forEach() 返回未定义，而 .some() 将返回 true 或 false 并且返回 true 后将停止迭代。

some() executes the callback function once for each element present in the array until it finds one where callback returns a true value. If such an element is found, some() immediately returns true. Otherwise, some() returns false.

fiddle : https://jsfiddle.net/mkarajohn/7ebr6pna/