javascript - 检查 DOM 中隐藏的父元素是否可见

Question

CSS:

#test {
        visibility: hidden;
        width: 400px;
        height: 400px;
        background-color: orange;
    }
    #subTest {
        width: 100px;
        height: 100px;
        background-color: gray;
    }

HTML:

<div id="test">
    <div id="subTest"></div>
</div>

JavaScript:

$(function() {
    var test = document.getElementById('test'),
        subTest = document.getElementById('subTest');

    console.log("getClientRects,length = " + subTest.getClientRects().length);
    console.log("offsetParent = " + subTest.offsetParent);
    console.log("JQuery isVisible = " + $("#subTest").is(":visible"));
});

结果:

getClientRects,length = 1

offsetParent = [object HTMLBodyElement]

JQuery isVisible = true

看来所有方法都无效。

那么如何检查#subTest是否可见？

Answer 1

这个

$('#subTest').css('visibility') == 'hidden' // true

由于父级是隐藏，它将级联到子级。