大家好,我遇到了一些代码问题。当在操作栏中单击溢出图标下的项目时,我需要打开一个新 Activity
下面是我的代码
我想知道我在编码中做错了什么地方以及解决方案是什么
提前致谢
<?xml version="1.0" encoding="utf-8"?>
<menu xmlns:android="http://schemas.android.com/apk/res/android">
<item
android:id="@id/item_option1"
android:title="option1"
android:onclick="gotocontact">
</item>
</menu>
// Main xml file
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout
xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:paddingLeft="@dimen/activity_horizontal_margin"
android:paddingRight="@dimen/activity_horizontal_margin"
android:paddingTop="@dimen/activity_vertical_margin"
android:paddingBottom="@dimen/activity_vertical_margin"
tools:context="com.example.mohammadzakriya.actionbar2.MainActivity">
</RelativeLayout>
MainActivity.java
package com.example.mohammadzakriya.actionbar2;
import android.content.Intent;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.Menu;
import android.view.MenuInflater;
import android.view.MenuItem;
import android.view.View;
public class MainActivity extends AppCompatActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
MenuInflater menuInflater = getMenuInflater();
menuInflater.inflate(R.menu.menu_main,menu);
return super.onCreateOptionsMenu(menu);
}
@Override
public boolean onOptionsItemSelected(MenuItem item ) {
switch(item.getItemId()){
case R.id.item_option1:
public void gotocontact(View view)
{
Intent intent = new Intent(this, Contact.class);
startActivity(intent);
}
break;
default:
break;
}
return super.onOptionsItemSelected(item);
}
}
Android list 文件
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.example.mohammadzakriya.actionbar2">
<application
android:allowBackup="true"
android:icon="@mipmap/ic_launcher"
android:label="@string/app_name"
android:supportsRtl="true"
android:theme="@style/AppTheme">
<activity android:name=".MainActivity">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<activity android:name=".Contact">
</activity>
</application>
</manifest>
最佳答案
以下应该没问题:
@Override
public boolean onOptionsItemSelected(MenuItem item ) {
switch(item.getItemId()){
case R.id.item_option1:
Intent intent = new Intent(this, Contact.class);
startActivity(intent);
break;
default:
break;
}
return super.onOptionsItemSelected(item);
}
关于javascript - 如何通过单击操作栏中溢出图标下的项目来调用其他 Activity ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38672330/