我有三个单选按钮,我想在 input:radio[].val !== 'samplename'
时分离一个 div。
这些是我的单选按钮
<div class="form-group">
<input checked="check" type="radio" value="Invididual" name="type_of_membership" id="radio-indi"> <label class="default-link" for="radio-indi">Individual</label>
<input type="radio" value="Institution" name="type_of_membership" id="radio-ins"> <label class="default-link" for="radio-ins">Institution</label>
<input type="radio" value="Corporation" name="type_of_membership" id="radio-corp"> <label class="default-link" for="radio-corp">Corporation</label>
</div>
这是我当前的 JS 脚本
var comapany_input = $("#company-div");
$("input[type='radio']").click(function() {
if (!$('input:radio').is(':checked').val() == "Corporation") {
comapany_input.detach();
} else {
comapany_input.appendTo("body");
comapany_input = null;
}
});
最佳答案
您需要使用
if($('input:radio:checked').val() != "Corporation") {
获取选中复选框的值。
if(!$('input:radio').is(':checked').val() == "Corporation") {
将抛出错误,因为 is
方法将返回一个 boolean
值,该值没有 val
方法。
var comapany_input = $("#company-div");
$("input[type='radio']").change(function() {
if (this.checked && this.value == 'Corporation') {
comapany_input.appendTo('body');
} else {
comapany_input.detach();
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="form-group">
<input checked="check" type="radio" value="Invididual" name="type_of_membership" id="radio-indi">
<label class="default-link" for="radio-indi">Individual</label>
<input type="radio" value="Institution" name="type_of_membership" id="radio-ins">
<label class="default-link" for="radio-ins">Institution</label>
<input type="radio" value="Corporation" name="type_of_membership" id="radio-corp">
<label class="default-link" for="radio-corp">Corporation</label>
</div>
<div id="company-div">company-div</div>
您可以隐藏/显示元素,例如
var comapany_input = $("#company-div");
$("input[type='radio']").change(function() {
comapany_input.toggle(this.value == 'Corporation')
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="form-group">
<input checked="check" type="radio" value="Invididual" name="type_of_membership" id="radio-indi">
<label class="default-link" for="radio-indi">Individual</label>
<input type="radio" value="Institution" name="type_of_membership" id="radio-ins">
<label class="default-link" for="radio-ins">Institution</label>
<input type="radio" value="Corporation" name="type_of_membership" id="radio-corp">
<label class="default-link" for="radio-corp">Corporation</label>
</div>
<div id="company-div">company-div</div>
关于javascript - 在 Jquery 中切换 detach() 选择器,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39240209/