我是一名新手,正在尝试构建德州扑克扑克游戏进行练习。为简单起见,假设我有 4 名玩家,我们处于第 4 轮/游戏,因此我的庄家筹码将位于玩家 4 处。另外,为了简单起见,我们开始在 DealerChip(即玩家 4)处进行交易。
var numberPlayers = 4;
var gameNumber = 4
var deck = ["1","3","4","2"]
var player4 = [];
var dealerChip = "player0";
if (gameNumber <= numberPlayers) {
dealerChip = "player" + gameNumber;
}
else {
var val = Math.floor((gameNumber-1) / numberPlayers);
dealerChip = "player" + gameNumber - numberPlayers * val;
};
function deal(toWhere) {
toWhere.push(deck[deck.length-1]);
deck.pop();
}
这是我的问题 - 当我尝试直接在 player4 上使用 deal 函数 (deal(player4);) 时,它工作正常。
但是当我在dealerChip上使用deal函数(deal(dealerChip);)时,它等于player4,它不起作用。
是不是因为dealerChip变量实际上是一个字符串?我该如何改变这个?抱歉,如果问题重复 - 我太新手了,甚至不知道要搜索什么...
最佳答案
这是我认为您正在尝试做的一个示例。您需要利用javascript's bracket notation .
//place properties into object.
var obj = {
numberPlayers: 4,
gameNumber: 4,
deck: ["1","3","4","2"],
player4: [],
dealerChip: "player0"
};
function deal(toWhere) {
toWhere.push(obj.deck[obj.deck.length-1]);
obj.deck.pop();
}
obj.dealerChip = "player4";
//now, to call deal()
//what you do and works because player4 is an array
deal(obj.player4);
//what you want to do; this access the property in the obj
//that has a name equal to the value of dealerChip.
//In this case, dealerChip has the value of "player4".
deal(obj[obj.dealerChip]);
//Therefore, it can be rewritten as:
deal(obj["player4"]);
//which can also be rewritten as:
deal(obj.player4);
//which is the same as the original you attempted
关于Javascript - 如何在函数中使用变量,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40564943/