在我的 Controller 中,我有一个分支数组,我需要将包含经纬度的位置对象附加到它的每个项目,即
{
"BANK": "B N P PARIBAS",
"IFSC": "BNPA0009009",
"MICR CODE": "400034002",
"BRANCH": "MUMBAI",
"ADDRESS": "FRENCH BANK BLDG.,62, HOMJI STREET, MUMBAI - 400 001",
"CONTACT": "0",
"CITY": "MUMBAI",
"DISTRICT": "MUMBAI",
"STATE": "MAHARASHTRA",
"ZIPCODE": "400 001",
"location": {
lat: ,
long:
}
},
我通过迭代分支 vi Angular forEach 并在 forEach 循环内的每个项目上调用 getLatLong 函数来实现此目的。
但是,该函数的控制/执行是这样的:在我从服务调用中获得任何结果之前,它会返回 deferred.promise。理想情况下,我希望从谷歌地图 API 获得位置对象,然后当它解析时,我希望将结果返回到 Controller 函数 getLatLong 并返回该位置对象,该对象又被分配给 forEach 循环中的 item.location 。
我的 Controller
module.exports = function(AppFactory, $q){
'use strict';
let ctrl = this;
ctrl.showList = true;
ctrl.branches = [
{
"BANK": "B N P PARIBAS",
"IFSC": "BNPA0009008",
"MICR CODE": "700034002",
"BRANCH": "KOLKATA",
"ADDRESS": "UNIT NO. 301, OFFICE NO. 2, 3RD FLOOR, AVANI SIGNATURE,91A/1, PARK STREET,KOLKATA :- 700016",
"CONTACT": "0",
"CITY": "KOLKATA",
"DISTRICT": "KOLKATA",
"STATE": "WEST BENGAL",
"ZIPCODE": "700016"
},
{
"BANK": "B N P PARIBAS",
"IFSC": "BNPA0009009",
"MICR CODE": "400034002",
"BRANCH": "MUMBAI",
"ADDRESS": "FRENCH BANK BLDG.,62, HOMJI STREET, MUMBAI - 400 001",
"CONTACT": "0",
"CITY": "MUMBAI",
"DISTRICT": "MUMBAI",
"STATE": "MAHARASHTRA",
"ZIPCODE": "400 001"
},
{
"BANK": "B N P PARIBAS",
"IFSC": "BNPA0009065",
"MICR CODE": "110034002",
"BRANCH": "DELHI",
"ADDRESS": "1ST FLOOR EAST TOWER (SOOD TOWER), 25, BARAKHAMBA ROAD,NEW DELHI :- 110001",
"CONTACT": "0",
"CITY": "DELHI",
"DISTRICT": "DELHI",
"STATE": "DELHI",
"ZIPCODE": "110001"
},
{
"BANK": "B N P PARIBAS",
"IFSC": "BNPA0009067",
"MICR CODE": "560034002",
"BRANCH": "BANGALORE",
"ADDRESS": "3RD FL,LANDMARK,21/15,M.G.ROAD,BANGLORE-560 001",
"CONTACT": "0",
"CITY": "BANGALORE",
"DISTRICT": "BANGALORE",
"STATE": "KARNATAKA",
"ZIPCODE": "560 001"
},
{
"BANK": "B N P PARIBAS",
"IFSC": "BNPA0009069",
"MICR CODE": "411034002",
"BRANCH": "PUNE",
"ADDRESS": "5 & 6,GODREJ MILLENIUM PARK,9,KOREGAON ROAD,PUNE-411 001",
"CONTACT": "0",
"CITY": "PUNE",
"DISTRICT": "PUNE",
"STATE": "MAHARASHTRA",
"ZIPCODE": "411 001"
}
]
// console.log(ctrl.branches);
function getLatLong(addressOrZip){
let results;
let deferred = $q.defer();
AppFactory.getLatLong(addressOrZip).then(function(res){
console.log(res);
deferred.resolve(res);
// if(res.results.length > 0){
// results = res.results[0].geometry.location;
// }else{
// results = res.results;
// }
// return results;
}, function(error){
deferred.reject(res);
});
return deferred.promise;
}
ctrl.toggleViews = function(){
ctrl.showList = !ctrl.showList;
if(!ctrl.showList){
angular.forEach(ctrl.branches, function(item){
let location = getLatLong(item.ZIPCODE );
console.log(location);
// let location = getLatLong( item.ADDRESS || item.ZIPCODE );
// if(location){
// item.location = location;
// }
})
console.log("Logging branches with location object...");
console.log(ctrl.branches);
}
}
}
然后在我的AppFactory中
let getLatLong = function(location){
// let defferred = $q.defer();
return $http({
url: "https://maps.googleapis.com/maps/api/geocode/json?address="+ location +"&key=AIzaSyDGyOrnNj8rrRFR92m6BEMvR24JiYoHtMs"
}).then(function(response){
return response.data;
// defferred.resolve(response.data);
}, function(error){
return error;
// defferred.reject(error);
});
// return defferred.promise;
}
我该如何解决这个问题?
最佳答案
getLatLong()
返回一个 Promise(这就是 $http
返回的内容),因此您需要在返回的 Promise 上使用 then()
访问响应数据
更改:
let location = getLatLong(item.ZIPCODE );
console.log(location);
致:
getLatLong(item.ZIPCODE ).then(function(data){
item.location = data;
console.log(item.location);
});
将由您来验证错误是否不会返回到此 then()
关于javascript - 更深入地理解 Promise,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40701447/