我有一个脚本,我想使用 ajax 处理表单数据。该脚本返回成功消息,但不返回错误消息。看看下面的脚本。
AJAX 脚本
$(document).ready(function() {
$("#submit").click(function() {
var dataString = {
flip: $("#flip").val(),
amount: $("#amount").val()
};
$.ajax({
type: "POST",
dataType : "json",
url: "flip-process.php",
data: dataString,
cache: true,
beforeSend: function(){
$("#submit").hide();
$("#loading").show();
$(".message").hide();
},
success: function(json){
setTimeout(function(){
$(".message").html(json.status).fadeIn();
$('#mywallet').html('$' + json.deduct);
$("#submit").show();
$("#loading").hide();
},3000);
}
});
return false;
});
});
PHP 脚本
<?php
session_start();
include'config/db.php';
$msg = null;
$sessionid = (!empty($_SESSION['login']))?$_SESSION['login']:null;
$wp = $pdo->prepare("SELECT set_cointoss_wp, set_cointoss_prob FROM settings");
$wp-> execute();
$sp = $wp->fetch();
$percent = $sp['set_cointoss_wp'];
$probablity = $sp['set_cointoss_prob'];
$bal = $pdo->prepare("SELECT mb_acbal, mb_wallet FROM mem_balance WHERE mb_id = :mem");
$bal-> bindValue(':mem', $sessionid);
$bal-> execute();
$bf = $bal->fetch();
$balance = $bf['mb_acbal'];
$wallet = $bf['mb_wallet'];
$coin = (!empty($_POST['flip']))?$_POST['flip']:null;
$amount = (!empty($_POST['amount']))?$_POST['amount']:null;
if($_POST){
if($wallet < $amount){
$msg = "<div class='message-error'>Sorry buddy! You have insufficient balance. Please <a href=''>recharge</a> your wallet.</div>";
}else{
$deduct = $wallet-$amount;
$prob = rand(1, 10);
//set new wallet balance after bet amount deduction
$stmt = $pdo->prepare("UPDATE mem_balance SET mb_wallet = :bal WHERE mb_user = :user");
$stmt-> bindValue(':bal', $deduct);
$stmt-> bindValue(':user', $sessionid);
$stmt-> execute();
if($coin == ''){
$msg = "<div class='message-error'>Sorry buddy! Fields cannot be left empty.</div>";
}else{
if($coin == "head"){
if($prob <= $probablity){
$result = 1;
}else{
$result = 2;
}
if($result == 1){
// win
$wa = $amount*$percent;
$win_amount = $wa/100;
$final_cash = $win_amount+$balance;
// update database with winning amount
$stmt = $pdo->prepare("UPDATE mem_balance SET mb_acbal = :bal WHERE mb_user = :user");
$stmt-> bindValue(':bal', $final_cash);
$stmt-> bindValue(':user', $sessionid);
$stmt-> execute();
$msg = "<div class='message-success'>Congratulations buddy! You won... <strong>$".$win_amount."</strong> has been credited to your account.</div>";
}else{
// loose
$msg = "<div class='message-error'>Sorry buddy! You lost... But do not loose hope. Try your luck again :)</div>";
}
}else{
if($prob <= $probablity){
$result = 2;
}else{
$result = 1;
}
if($result == 1){
// loose
$msg = "<div class='message-error'>Sorry buddy! You lost... But do not loose hope. Try your luck again :)</div>";
}else{
// win
$wa = $amount*$percent;
$win_amount = $wa/100;
$final_cash = $win_amount+$balance;
// update database with winning amount
$stmt = $pdo->prepare("UPDATE mem_balance SET mb_acbal = :bal WHERE mb_user = :user");
$stmt-> bindValue(':bal', $final_cash);
$stmt-> bindValue(':user', $sessionid);
$stmt-> execute();
$msg = "<div class='message-success'>Congratulations buddy! You won... <strong>$".$win_amount."</strong> has been credited to your account.</div>";
}
}
}
}
echo json_encode(array('status' => $msg, 'deduct' => $deduct));
}
?>
在上面的脚本中,当 if($wallet < $amount)
条件为 false 且 else
执行条件后,脚本工作正常并返回 <div class='message-success'>
按要求。但是,如果if($wallet < $amount)
条件为 true 那么它不会返回 <div class='message-error'>
并且加载图像继续移动(就像在等待响应一样),但没有收到任何响应作为返回。我被困了几天,但无法找到任何解决方案。请帮忙。
最佳答案
我不确定,但我认为在你的 php 脚本中 $deduct 已在 else block 内声明。
因此,当脚本执行并且 if ($wallet < $amount) 条件计算为 true 时,则跳过 else 部分,直接返回:-
return echo json_encode(array(
'status' => $msg,
'deduct' => $deduct
));
因此可能会出现 $deduct 无法识别的情况。尝试通过在 if block 之前声明 $deduct 来执行。
关于javascript - PHP AJAX 脚本无法在所有条件下正常工作,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43165200/