javascript - 对 D3 中可折叠树形图中父节点上的 "Number of child' s 进行编号

标签 javascript jquery html css d3.js

我正在使用 D3 js 构建一个可折叠树形图，我已经实现了部分要求，此外我想显示该特定父节点的子节点数量。

像这样

Here is the image

但是我无法破解这个逻辑，如果我能在这里得到一些帮助那就太好了..

谢谢

这是我在没有编号的情况下实现的代码......

tree_d3.js

var treeData =
  {
    "name": "Top Level",
    "children": [
      { 
        "name": "Level 2: A",
        "children": [
          { "name": "Son of A" },
          { "name": "Daughter of A" }
        ]
      },
      { "name": "Level 2: B",
      "children": [
          { "name": "Son of B" },
          { "name": "Daughter of B" }
        ]
      },
    ]
  };

// Set the dimensions and margins of the diagram
var margin = {top: 20, right: 90, bottom: 30, left: 90},
    width = 960 - margin.left - margin.right,
    height = 500 - margin.top - margin.bottom;

// append the svg object to the body of the page
// appends a 'group' element to 'svg'
// moves the 'group' element to the top left margin
var svg = d3.select(".tree").append("svg")
    .attr("width", width + margin.right + margin.left)
    .attr("height", height + margin.top + margin.bottom)
  .append("g")
    .attr("transform", "translate("
          + margin.left + "," + margin.top + ")");

var i = 0,
    duration = 750,
    root;

// declares a tree layout and assigns the size
var treemap = d3.tree().size([height, width]);

// Assigns parent, children, height, depth
root = d3.hierarchy(treeData, function(d) { return d.children; });
root.x0 = height / 2;
root.y0 = 0;

// Collapse after the second level
root.children.forEach(collapse);

update(root);

// Collapse the node and all it's children
function collapse(d) {
  if(d.children) {
    d._children = d.children
    d._children.forEach(collapse)
    d.children = null
  }
}

function update(source) {

  // Assigns the x and y position for the nodes
  var treeData = treemap(root);

  // Compute the new tree layout.
  var nodes = treeData.descendants(),
      links = treeData.descendants().slice(1);

  // Normalize for fixed-depth.
  nodes.forEach(function(d){ d.y = d.depth * 180});

  // ****************** Nodes section ***************************

  // Update the nodes...
  var node = svg.selectAll('g.node')
      .data(nodes, function(d) {return d.id || (d.id = ++i); });

  // Enter any new modes at the parent's previous position.
  var nodeEnter = node.enter().append('g')
      .attr('class', 'node')
      .attr("transform", function(d) {
        return "translate(" + source.y0 + "," + source.x0 + ")";
    })
    .on('click', click);

  // Add Circle for the nodes
  nodeEnter.append('circle')
      .attr('class', 'node')
      .attr('r', 1e-6)
      .style("fill", function(d) {
          return d._children ? "lightsteelblue" : "#fff";
      });

  // Add labels for the nodes
  nodeEnter.append('text')
      .attr("dy", ".35em")
      .attr("x", function(d) {
          return d.children || d._children ? -13 : 13;
      })
      .attr("text-anchor", function(d) {
          return d.children || d._children ? "end" : "start";
      })
      .text(function(d) { return d.data.name; });

  // UPDATE
  var nodeUpdate = nodeEnter.merge(node);

  // Transition to the proper position for the node
  nodeUpdate.transition()
    .duration(duration)
    .attr("transform", function(d) { 
        return "translate(" + d.y + "," + d.x + ")";
     });

  // Update the node attributes and style
  nodeUpdate.select('circle.node')
    .attr('r', 10)
    .style("fill", function(d) {
        return d._children ? "lightsteelblue" : "#fff";
    })
    .attr('cursor', 'pointer');


  // Remove any exiting nodes
  var nodeExit = node.exit().transition()
      .duration(duration)
      .attr("transform", function(d) {
          return "translate(" + source.y + "," + source.x + ")";
      })
      .remove();

  // On exit reduce the node circles size to 0
  nodeExit.select('circle')
    .attr('r', 1e-6);

  // On exit reduce the opacity of text labels
  nodeExit.select('text')
    .style('fill-opacity', 1e-6);

  // ****************** links section ***************************

  // Update the links...
  var link = svg.selectAll('path.link')
      .data(links, function(d) { return d.id; });

  // Enter any new links at the parent's previous position.
  var linkEnter = link.enter().insert('path', "g")
      .attr("class", "link")
      .attr('d', function(d){
        var o = {x: source.x0, y: source.y0}
        return diagonal(o, o)
      });

  // UPDATE
  var linkUpdate = linkEnter.merge(link);

  // Transition back to the parent element position
  linkUpdate.transition()
      .duration(duration)
      .attr('d', function(d){ return diagonal(d, d.parent) });

  // Remove any exiting links
  var linkExit = link.exit().transition()
      .duration(duration)
      .attr('d', function(d) {
        var o = {x: source.x, y: source.y}
        return diagonal(o, o)
      })
      .remove();

  // Store the old positions for transition.
  nodes.forEach(function(d){
    d.x0 = d.x;
    d.y0 = d.y;
  });

  // Creates a curved (diagonal) path from parent to the child nodes
  function diagonal(s, d) {

    path = `M ${s.y} ${s.x}
            C ${(s.y + d.y) / 2} ${s.x},
              ${(s.y + d.y) / 2} ${d.x},
              ${d.y} ${d.x}`

    return path
  }

  // Toggle children on click.
  function click(d) {
    if (d.children) {
        d._children = d.children;
        d.children = null;
      } else {
        d.children = d._children;
        d._children = null;
      }
    update(d);
  }
}

tree_d3.css

.node circle {
  fill: #fff;
  stroke: steelblue;
  stroke-width: 3px;
}

.node text {
  font: 12px sans-serif;
}

.link {
  fill: none;
  stroke: #ccc;
  stroke-width: 2px;
}

tree_d3.html

<html>
<meta charset="UTF-8">
<body>
  <div class="tree">
  </div>
</body>
</html>

这是我在 CodePen 中的代码的链接...

https://codepen.io/hari2609/pen/YxdYwx?editors=1000

最佳答案

希望这有帮助。

  nodeEnter.append('text') 
    .attr("dy", ".35em")
    .attr("x", function(d) {
          return d.children || d._children ? 4 : -4;
     })
    .attr("text-anchor", function(d) {
      return d.children || d._children ? "end" : "start";
    })
    .text(function(d) {
      var children = d.children || d._children;
      return children ? children.length : 0;
    });


var treeData = {
  "name": "Top Level",
  "children": [{
      "name": "Level 2: A",
      "children": [{
          "name": "Son of A"
        },
        {
          "name": "Daughter of A"
        }
      ]
    },
    {
      "name": "Level 2: B",
      "children": [{
          "name": "Son of B"
        },
        {
          "name": "Daughter of B"
        }
      ]
    },
  ]
};

// Set the dimensions and margins of the diagram
var margin = {
    top: 20,
    right: 90,
    bottom: 30,
    left: 90
  },
  width = 960 - margin.left - margin.right,
  height = 500 - margin.top - margin.bottom;

// append the svg object to the body of the page
// appends a 'group' element to 'svg'
// moves the 'group' element to the top left margin
var svg = d3.select(".tree").append("svg")
  .attr("width", width + margin.right + margin.left)
  .attr("height", height + margin.top + margin.bottom)
  .append("g")
  .attr("transform", "translate(" +
    margin.left + "," + margin.top + ")");

var i = 0,
  duration = 750,
  root;

// declares a tree layout and assigns the size
var treemap = d3.tree().size([height, width]);

// Assigns parent, children, height, depth
root = d3.hierarchy(treeData, function(d) {
  return d.children;
});
root.x0 = height / 2;
root.y0 = 0;

// Collapse after the second level
root.children.forEach(collapse);

update(root);

// Collapse the node and all it's children
function collapse(d) {
  if (d.children) {
    d._children = d.children
    d._children.forEach(collapse)
    d.children = null
  }
}

function update(source) {

  // Assigns the x and y position for the nodes
  var treeData = treemap(root);

  // Compute the new tree layout.
  var nodes = treeData.descendants(),
    links = treeData.descendants().slice(1);

  // Normalize for fixed-depth.
  nodes.forEach(function(d) {
    d.y = d.depth * 180
  });

  // ****************** Nodes section ***************************

  // Update the nodes...
  var node = svg.selectAll('g.node')
    .data(nodes, function(d) {
      return d.id || (d.id = ++i);
    });

  // Enter any new modes at the parent's previous position.
  var nodeEnter = node.enter().append('g')
    .attr('class', 'node')
    .attr("transform", function(d) {
      return "translate(" + source.y0 + "," + source.x0 + ")";
    })
    .on('click', click);

  // Add Circle for the nodes
  nodeEnter.append('circle')
    .attr('class', 'node')
    .attr('r', 1e-6)
    .style("fill", function(d) {
      return d._children ? "lightsteelblue" : "#fff";
    });

  // Add labels for the nodes
  nodeEnter.append('text')
    .attr("dy", ".35em")
    .attr("x", function(d) {
      return d.children || d._children ? -13 : 13;
    })
    .attr("text-anchor", function(d) {
      return d.children || d._children ? "end" : "start";
    })
    .text(function(d) {
      return d.data.name;
    });

  nodeEnter.append('text') 
    .attr("dy", ".35em")
    .attr("x", function(d) {
          return d.children || d._children ? 4 : -4;
     })
    .attr("text-anchor", function(d) {
      return d.children || d._children ? "end" : "start";
    })
    .text(function(d) {
      var children = d.children || d._children;
      return children ? children.length : 0;
    });

  // UPDATE
  var nodeUpdate = nodeEnter.merge(node);

  // Transition to the proper position for the node
  nodeUpdate.transition()
    .duration(duration)
    .attr("transform", function(d) {
      return "translate(" + d.y + "," + d.x + ")";
    });

  // Update the node attributes and style
  nodeUpdate.select('circle.node')
    .attr('r', 10)
    .style("fill", function(d) {
      return d._children ? "lightsteelblue" : "#fff";
    })
    .attr('cursor', 'pointer');


  // Remove any exiting nodes
  var nodeExit = node.exit().transition()
    .duration(duration)
    .attr("transform", function(d) {
      return "translate(" + source.y + "," + source.x + ")";
    })
    .remove();

  // On exit reduce the node circles size to 0
  nodeExit.select('circle')
    .attr('r', 1e-6);

  // On exit reduce the opacity of text labels
  nodeExit.select('text')
    .style('fill-opacity', 1e-6);

  // ****************** links section ***************************

  // Update the links...
  var link = svg.selectAll('path.link')
    .data(links, function(d) {
      return d.id;
    });

  // Enter any new links at the parent's previous position.
  var linkEnter = link.enter().insert('path', "g")
    .attr("class", "link")
    .attr('d', function(d) {
      var o = {
        x: source.x0,
        y: source.y0
      }
      return diagonal(o, o)
    });

  // UPDATE
  var linkUpdate = linkEnter.merge(link);

  // Transition back to the parent element position
  linkUpdate.transition()
    .duration(duration)
    .attr('d', function(d) {
      return diagonal(d, d.parent)
    });

  // Remove any exiting links
  var linkExit = link.exit().transition()
    .duration(duration)
    .attr('d', function(d) {
      var o = {
        x: source.x,
        y: source.y
      }
      return diagonal(o, o)
    })
    .remove();

  // Store the old positions for transition.
  nodes.forEach(function(d) {
    d.x0 = d.x;
    d.y0 = d.y;
  });

  // Creates a curved (diagonal) path from parent to the child nodes
  function diagonal(s, d) {

    path = `M ${s.y} ${s.x}
            C ${(s.y + d.y) / 2} ${s.x},
              ${(s.y + d.y) / 2} ${d.x},
              ${d.y} ${d.x}`

    return path
  }

  // Toggle children on click.
  function click(d) {
    if (d.children) {
      d._children = d.children;
      d.children = null;
    } else {
      d.children = d._children;
      d._children = null;
    }
    update(d);
  }
}
.node circle {
  fill: #fff;
  stroke: steelblue;
  stroke-width: 3px;
}

.node text {
  font: 12px sans-serif;
}

.link {
  fill: none;
  stroke: #ccc;
  stroke-width: 2px;
}
<script src="https://d3js.org/d3.v4.min.js"></script>
<div class="tree">
</div>

关于javascript - 对 D3 中可折叠树形图中父节点上的 "Number of child' s 进行编号，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/46765068/

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