javascript - 奇怪的是，React Native 没有显示错误

Question

我的 React Native 应用程序遇到了奇怪的情况。 有问题的代码部分是这样的:

const request = async (options) => {
  const defaults = {baseURL: 'base URL'}
  let token = await AsyncStorage.getItem('token');
  console.log('this is logged')
  if(token) {
      console.log("this is logged")
      const headers = {
    'TokenAuth': token
  }
      Object.assign(defaults, headers: headers);
  }
  console.log('this is NOT logged anymore')
  options = Object.assign({}, defaults, options);
};

这个想法是我看不到任何地方的 JavaScript 错误。

错误发生在 Object.assign(defaults, headers); 为什么我看不到？

谢谢。

Answer 1

这是整个组件:

import constants from './../constants/constants';
import axios from 'axios';
import { AsyncStorage } from 'react-native';

import * as Utils from '../configs/utils'

const request = async (options) => {
  const defaults = {baseURL: constants.BASE_URL}
  let token = await AsyncStorage.getItem('token');
  if(token) {
      const headers = {'TokenAuth': token}
      Object.assign(defaults, {headers: headers});
  }
  options = Object.assign({}, defaults, options);

  return axios(options)
        .then(response => {
          return response.data 
         } )
        .catch( error => {
          if (error.response.status == 401) {
            Utils.deleteToken();
          }
          let errResponse = 'Bad Error'
          throw errResponse;
        });
};
export function getAllTodos() {
  return request({method: 'get', 
                baseURL: constants.BASE_URL,
                url: '/api/items',
                })
}