javascript - 从对象返回最佳匹配

Question

在对象数组中:

const candidates = [
   {
     "id": "a4b7d559-8437-4bec-a6d3-65821d50a0b5",
     "name": "alpha",
     "skills": [
        "Go",
        "Ruby",
        "Python" 
     ]
  },
 {
     "id": "a4b7d559-8437-4bec-a6d3-6554880a0b5",
     "name": "metta",
     "skills": [
        "Express",
        "Ruby",
        "Python",
        "swift"
     ]
  },
  {
     "id": "a4b7d559-8437-4bec-a6d3-65821d50a0b5",
     "name": "Thitha",
     "skills": [
        "Javascript",
        "React",
        "Express",
        "Node"
     ]
  },
]

我想编写一个函数，当我将多个技能集作为数组传递时，即 ["Javascript", "Express", "Node"] 我返回与我的匹配的候选人在这种情况下，技能组将是最后一个 Thitha。我想在 API 的 req.query 端点中实现此函数。请帮忙。

返回的结果是:-

{
     "id": "a4b7d559-8437-4bec-a6d3-65821d50a0b5",
     "name": "Thitha",
     "skills": [
        "Javascript",
        "React",
        "Express",
        "Node"
     ]
  }

到目前为止我尝试过的:-

function getCandidate(subSet, set){
   const filtered = Object.values(set).filter(key => 
    subSet.includes(key)).reduce((obj, key) => {
    obj[key] = set[key]
    return obj
 }, {})
}

Answer 1

可以过滤数组，其中每个项都存在:

let filters = ["Javascript", "Express", "Node"];
const result = candidates.filter(f => filters.every(e=> f.skills.some(s => s == e)));

举个例子:

const candidates = [
   {
     "id": "a4b7d559-8437-4bec-a6d3-65821d50a0b5",
     "name": "alpha",
     "skills": [
        "Go",
        "Ruby",
        "Python"
     ]
  },
 {
     "id": "a4b7d559-8437-4bec-a6d3-6554880a0b5",
     "name": "metta",
     "skills": [
        "Express",
        "Ruby",
        "Python",
        "swift"
     ]
  },
  {
     "id": "a4b7d559-8437-4bec-a6d3-65821d50a0b5",
     "name": "Thitha",
     "skills": [
        "Javascript",
        "React",
        "Express",
        "Node"
     ]
  },
];

let filters = ["Javascript", "Express", "Node"];
const result = candidates.filter(f => filters.every(e=> f.skills.some(s => s == e)));

console.log(result);