现在，我正在为类(class)表制定时间表。我的想法是设置 FullCalendar仅查看 agendaWeek 并设置其他内容的格式。关于如何获取和添加事件的编程方面是我不知道的，因为我不会为此实例使用任何日期。
这是时间表表:
| schedid | subjectcode | prof_id | day | start_time | end_time | duration | room |
-------------------------------------------------------------------------------------------
| 1 | TECHNO | 16-00001 | Monday | 11:00:00 | 14:00:00 | 3 | SL |
| 2 | TECHNO | 16-00001 | Tuesday | 10:30:00 | 13:30:00 | 3 | SL |
这就是我要实现的目标:
我已经阅读了文档，阅读的越多，我就越不知道该怎么做，而且我真的不知道如何实现它，因为 FullCalendar 取决于日期。非常感谢任何建议和帮助。
编辑:
这是我的 FullCalendar 脚本:
$(document).ready(function() {
$("#add-sched").fullCalendar({
header: false,
columnFormat: 'dddd',
allDaySlot: false,
hiddenDays: [0],
defaultView: 'agendaWeek',
minTime: '07:00:00',
maxTime: '21:00:00',
editatble: true,
events: [ // values will be coming from an ajax call so I'm just placing here what inputs I would like
{
title: 'Event',
start: 'MondayT11:00:00', //what I would like to input
end: 'MondayT11:00:00',
// start: '2016-12-12T11:00:00',
// end: '2016-12-12T14:00:00',
editable: true
}
]
});
});
最佳答案
如果我理解你的目标，你需要一周的静态日历。事件不会按日期更改，只会按日期名称更改。
所以我重写了以前的解决方案。在此变体中，形成了关联数组，其中包含当前周的日期，键是日期的名称。可以通过日期名称访问日期，因此您不需要在数据库中存储日期 请看看这个。
HTML页面(非重要代码):
<html>
<head>
<meta charset='utf-8' />
<link href='/something/fullcalendar.min.css' rel='stylesheet' />
<link href='/something/fullcalendar.print.min.css' rel='stylesheet' media='print' />
<script src='/something/lib/moment.min.js'></script>
<script src='/something/lib/jquery.min.js'></script>
<script src='/something/fullcalendar.min.js'></script>
<script src='/something/initCalendar.js'></script> <!-- Script with all important stuff-->
<style>
body {
margin: 40px 10px;
padding: 0;
font-family: "Lucida Grande",Helvetica,Arial,Verdana,sans-serif;
font-size: 14px;
}
#calendar {
max-width: 900px;
margin: 0 auto;
}
</style>
</head>
<body>
<div id='calendar'></div>
</body>
</html>
initCalendar.js 代码(最重要的部分):
Date.prototype.getDaysOfCurrentWeek = function(start)
{
// Array of all days of week
var days = [ "Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"];
// Calculates date of first day of current week
start = start || 0;
var today = new Date(this.setHours(0, 0, 0, 0));
var day = today.getDay() - start;
var date = today.getDate() - day;
// Then we are calculating all dates of current week and then reformat them into ISOO
var daysOfWeek = new Object();
for(i = 0; i < 8; i++) {
tmp = new Date(today.setDate(date+i));
daysOfWeek[days[i]] = tmp.getFullYear()+'-'+(tmp.getMonth()+1)+'-'+tmp.getDate();
}
return daysOfWeek;
}
var days = new Date().getDaysOfCurrentWeek(); // gets array like ('nameOfDay' => 0000-00-00)
$(document).ready(function(){
$('#calendar').fullCalendar({
header: false,
columnFormat: 'dddd',
allDaySlot: false,
hiddenDays: [0],
defaultView: 'agendaWeek',
minTime: '07:00:00',
maxTime: '21:00:00',
editatble: true,
});
$.post( "getevents2.php",
{'getEvents': 1},
function(data) {
var array = JSON.parse(data);
for(i = 0; i < array.length; i++) {
$('#calendar').fullCalendar( 'renderEvent', {
title: 'Sometitle',
start: days[array[i]['day']]+'T'+array[i]['start_time'], // here we are setting needed date from array 'days' by day's name which we got from database
end: days[array[i]['day']]+'T'+array[i]['end_time'] // here's the same
} );
}
}
);
});
getevents2.php的PHP代码:
if(isset($_POST['getEvents'])) {
$result = $db->query("SELECT * FROM `calendar`");
$return = array();
while($row = $result->fetch_assoc()) {
$return[] = $row;
}
echo json_encode($return);
}
这就是您所需要的吗？还是我又做错了？
关于php - 使用没有日期的 FullCalendar，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/41115235/