javascript - 函数返回值未定义

Question

我有这个功能:

function addressVerification() {

  var del;

  let addVer = $('#add_verified').val();
  let maddVer = $('#madd_verified').val();

  if (addVer == "yes" && maddVer == "yes") {
      del = true;
  } else {
      del = false;
  }
  return del;
}

当我调用它时:

$('#add_verified').change(function(){
  var ver = addressVerification();
  console.info("This is the returned value from the verified address function: "+ ver);
});

它返回为“未定义”。

我做错了什么？

Answer 1

您有语法错误

function addressVerification() {
    var del;
    let addVer = $('#add_verified').val();
    let maddVer = $('#madd_verified').val();

    if (addVer == "yes" && maddVer == "yes") {
        del = true;
    } else {
        del = false;
    }
  } . <----- This is closing the function, ant thus, returning undefined
  return del;
}