我试图通过将每个名称存储在两个 UNION 表(Accesses 和 Reports)的数组中来显示每张票证的受让人名称(来自 Users 表的外键),但它给了我这个错误。错误异常 未定义的属性:stdClass::$assignee。
//HomeController
$accesses = DB::table('accesses')
->select(array('id', 'fullname','emp_id','shift','state','resolved_at', 'closed_at','assigned_to'))
->where('state','=','Assigned');
$all = DB::table('reports')
->select(array('id', 'fullname','emp_id','shift','state','resolved_at', 'closed_at','assigned_to'))
->union($accesses)
->where('state', '=', 'Assigned')
->get();
$names[] = array();
foreach ($all as $one)//store in array to display in a chart
{
$names[] = $one->assignee->name; //error here
}
//Report Model
public function assignee()
{
return $this->belongsTo(User::class, 'assigned_to');
}
//Access Model
public function assignee()
{
return $this->belongsTo(User::class, 'assigned_to');
}
//Report Migration
public function up()
{
Schema::create('reports', function (Blueprint $table) {
$table->increments('id');
$table->integer('user_id')->nullable();
$table->string('fullname');
$table->string('emp_id');
$table->string('shift');
$table->longText('report');
$table->string('status')->default('Pending'); //Pending, Approved
$table->string('state')->default('Open'); //Open, Assigned, Resolved, Closed
$table->date('resolved_at')->nullable();
$table->date('closed_at')->nullable();
$table->integer('assigned_to')->nullable();
$table->longText('action')->nullable();
$table->timestamps();
});
}
//Access Migration
public function up()
{
Schema::create('accesses', function (Blueprint $table) {
$table->increments('id');
$table->integer('user_id')->nullable();
$table->string('fullname');
$table->string('emp_id');
$table->string('shift');
$table->string('request');
$table->longText('note')->nullable();
$table->string('status')->default('Pending'); //Pending, Approved
$table->string('state')->default('Open'); //Open, Assigned, Resolved, Closed
$table->date('resolved_at')->nullable();
$table->date('closed_at')->nullable();
$table->integer('assigned_to')->nullable();
$table->longText('action')->nullable();
$table->timestamps();
});
}
最佳答案
您应该使用 merge
集合方法:
$accesses = Access::select(array('id', 'fullname','emp_id','shift','state','resolved_at', 'closed_at','assigned_to'))
->where('state','=','Assigned')
->get();
$reports = Report::select(array('id', 'fullname','emp_id','shift','state','resolved_at', 'closed_at','assigned_to'))
->where('state', '=', 'Assigned')
->get();
$all = $accesses->merge($reports);
关于php - 拉维尔 5.4 : Cannot retrieve data from a relationship,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45406179/