javascript - Jquery - if 语句中的运算符

Question

我正在尝试将表单提交到不同的位置，具体取决于已提交的(两个)表单字段。

当两个字段都有值时，它会起作用，但当只有一个字段有值时，它总是提交到 vendor/类别/URL。这是我的代码。

$('#suppliersForm').submit(function() {

catVal = $('#category').val()
keywordVal = $('#keywords').val()

if( $('#category').val() && $('#keywords').val() ) 
{
var searchString = 'http://<cfoutput>#cgi.server_name#</cfoutput>/suppliers/searchresults/' + catVal + '/' + keywordVal
window.location.replace(searchString);
}
else if( $('#category').val() || $('#keywords').val() )
{   
var searchString = 'http://<cfoutput>#cgi.server_name#</cfoutput>/suppliers/category/' + catVal
window.location.replace(searchString);  
}
else if( $('#keywords').val() || $('#category').val() )
{   
var searchString = 'http://<cfoutput>#cgi.server_name#</cfoutput>/suppliers/keywords/' + keywordVal
window.location.replace(searchString);  
}
return false;
});

如有任何帮助，我们将不胜感激

Answer 1

$('#suppliersForm').submit(function() {

var catVal = $('#category').val();
var keywordVal = $('#keywords').val();
var searchString = "";

if( catVal != "" && keywordVal !="" ) 
{
     searchString = 'http://<cfoutput>#cgi.server_name#</cfoutput>/suppliers/searchresults/' + catVal + '/' + keywordVal;
}
else if( catVal != ""  )
{   
     searchString = 'http://<cfoutput>#cgi.server_name#</cfoutput>/suppliers/category/' + catVal;
}
else if( keywordVal != "" )
{   
     searchString = 'http://<cfoutput>#cgi.server_name#</cfoutput>/suppliers/keywords/' + keywordVal;
}
window.location.replace(searchString);  
return false;
});