javascript - 获取 json 数据中的嵌套映射

标签 javascript jquery json

我有这样的 JSON 数据:

var data = '{"credit":{"@code":"NT2C8FFC","card":"NT2C8FFC","credit":"149.96","amount":"149.96","disabled":"0","expired":"2011-02-15 10:21:18","user":"xxxx","issued":"2010-02-15 10:21:18","orderid":[],"fromorder":[],"email":"xxxx","phone":[],"state":[],"address":[],"city":[],"zip":[],"country":[],"customerid":"xxx","order":"xxx","order_date":"2010-01-23 00:00:00","reason":"Product Not Working as Expected","source":"xxx","first":[],"last":[],"notes":[]}}'

它实际上以 JSON 形式返回给我。我只是为了举例而将其展示在这里。我可以使用 data["credit"] 来获取名为 credit 的元素,但这只能获取我的信息:

{"@code":"NT2C8FFC","card":"NT2C8FFC","credit":"149.96","amount":"149.96","disabled":"0","expired":"2011-02-15 10:21:18","user":"xxxx","issued":"2010-02-15 10:21:18","orderid":[],"fromorder":[],"email":"xxxx","phone":[],"state":[],"address":[],"city":[],"zip":[],"country":[],"customerid":"xxx","order":"xxx","order_date":"2010-01-23 00:00:00","reason":"Product Not Working as Expected","source":"xxx","first":[],"last":[],"notes":[]}

如何深入到一个镜头? data["credit"]["credit"] 不是正确的语法。其结果是未定义。我知道我已经很接近了,但不记得剩下的了。目标是从 JSON 数据中获取 149.96

最佳答案

现在您可以使用alert(data.credit.credit)

        var data = '{"credit":{"@code":"NT2C8FFC","card":"NT2C8FFC","credit":"149.96","amount":"149.96","disabled":"0","expired":"2011-02-15 10:21:18","user":"xxxx","issued":"2010-02-15 10:21:18","orderid":[],"fromorder":[],"email":"xxxx","phone":[],"state":[],"address":[],"city":[],"zip":[],"country":[],"customerid":"xxx","order":"xxx","order_date":"2010-01-23 00:00:00","reason":"Product Not Working as Expected","source":"xxx","first":[],"last":[],"notes":[]}}';
        eval("data=" + data);
        alert(data.credit.credit);

您还可以使用 data = JSON.parse(data); 将字符串转换为 Json,但这存在浏览器兼容性问题。

这些是支持的浏览器

  • 火狐 (Mozilla) 3.5
  • Internet Explorer 8
  • Chrome
  • 歌剧 10
  • 列出项目
  • Safari 4

旧版本不支持。

关于javascript - 获取 json 数据中的嵌套映射,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15918725/

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