我正在尝试添加红色圆圈，该圆圈将出现在我的力定向图中的节点之间的线上(可能居中)。
我试图通过将其添加到 line.link 来解决这个问题，就像我使用新变量添加行一样:
var linkcirc = vis.selectAll("line.link")
.data(data.links)
.enter().append("circle")
.attr("r",5)
.attr("cy", function(d) { return d.target.y; })
.attr("cx", function(d) { return d.source.x+60; })
.attr("class", "linecircle")
.attr("fill","red");
并在强制勾选时我添加:
linkcirc.attr("cy", function(d) { return d.target.y; })
.attr("cx", function(d) { return d.source.x+60; })
它们确实出现了，但我不知道如何将它们放置在正确的位置，在节点的中间...如何使用源、目标位置或其他位置，以便红色圆圈显示在节点的中心链接？...
你可以在这里看到我现在的情况:http://jsfiddle.net/nAAbn/
脚本如下所示:
var data = {"nodes":[
{"name":"YHO", "full_name":"Yahoo", "type":1, "slug": "www.yahoo.com", "entity":"company", "img_hrefD":"", "img_hrefL":""},
{"name":"GGL", "full_name":"Google", "type":2, "slug": "www.google.com", "entity":"company", "img_hrefD":"", "img_hrefL":""},
{"name":"BNG", "full_name":"Bing", "type":2, "slug": "www.bing.com", "entity":"company", "img_hrefD":"", "img_hrefL":""},
{"name":"YDX", "full_name":"Yandex", "type":2, "slug": "www.yandex.com", "entity":"company", "img_hrefD":"", "img_hrefL":""},
{"name":"Desc1", "type":4, "slug": "", "entity":"description"},
{"name":"Desc2", "type":4, "slug": "", "entity":"description"},
{"name":"Desc4", "type":4, "slug": "", "entity":"description"},
{"name":"CEO", "prefix":"Mr.", "fst_name":"Jim", "snd_name":"Bean", "type":3, "slug": "", "entity":"employee"},
{"name":"ATT", "prefix":"Ms.", "fst_name":"Jenna", "snd_name":"Jameson", "type":3, "slug": "", "entity":"employee"},
{"name":"CTO", "prefix":"Mr.", "fst_name":"Lucky", "snd_name":"Luke", "type":3, "slug": "", "entity":"employee"},
{"name":"CDO", "prefix":"Ms.", "fst_name":"Pamela", "snd_name":"Anderson", "type":3, "slug": "", "entity":"employee"},
{"name":"CEO", "prefix":"Mr.", "fst_name":"Nacho", "snd_name":"Vidal", "type":3, "slug": "", "entity":"employee"},
],
"links":[
{"source":0,"target":4,"value":1,"distance":5},
{"source":0,"target":5,"value":1,"distance":5},
{"source":0,"target":6,"value":1,"distance":5},
{"source":1,"target":4,"value":1,"distance":5},
{"source":2,"target":5,"value":1,"distance":5},
{"source":3,"target":6,"value":1,"distance":5},
{"source":7,"target":3,"value":10,"distance":6},
{"source":8,"target":3,"value":10,"distance":6},
{"source":9,"target":1,"value":10,"distance":6},
{"source":10,"target":1,"value":10,"distance":6},
{"source":11,"target":2,"value":10,"distance":6},
]
}
var w = 560,
h = 500,
radius = d3.scale.log().domain([0, 312000]).range(["10", "50"]);
var vis = d3.select("body").append("svg:svg")
.attr("width", w)
.attr("height", h);
//d3.json(data, function(json) {
var force = self.force = d3.layout.force()
.nodes(data.nodes)
.links(data.links)
.linkDistance(function(d) { return (d.distance*20); })
//.friction(0.5)
.charge(-250)
.size([w, h])
.start();
var link = vis.selectAll("line.link")
.data(data.links)
.enter().append("svg:line")
.style("stroke","blue")
.attr("class", function (d) { return "link" + d.value +""; })
.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; })
var linkcirc = vis.selectAll("line.link")
.data(data.links)
.enter().append("circle")
.attr("r",5)
.attr("cy", function(d) { return d.target.y; })
.attr("cx", function(d) { return d.source.x+60; })
.attr("class", "linecircle")
.attr("fill","red");
function openLink() {
return function(d) {
var url = "";
if(d.slug != "") {
url = d.slug
} //else if(d.type == 2) {
//url = "clients/" + d.slug
//} else if(d.type == 3) {
//url = "agencies/" + d.slug
//}
window.open("//"+url)
}
}
var node = vis.selectAll("g.node")
.data(data.nodes)
.enter().append("svg:g")
.attr("class", "node")
.call(force.drag);
node.append("circle")
.attr("class", function(d){ return "node type"+d.type})
.attr("r",function(d){if(d.entity == "description"){ return 6 } else { return 18 }})
//.on("mouseover", expandNode);
//.style("fill", function(d) { return fill(d.type); })
node.append("svg:image")
.attr("class", function(d){ return "circle img_"+d.name })
.attr("xlink:href", function(d){ return d.img_hrefD})
.attr("x", "-36px")
.attr("y", "-36px")
.attr("width", "70px")
.attr("height", "70px")
.on("click", openLink())
.on("mouseover", function (d) { if(d.entity == "company")
{
d3.select(this).attr("width", "90px")
.attr("x", "-46px")
.attr("y", "-36.5px")
.attr("xlink:href", function(d){ return d.img_hrefL});
}
})
.on("mouseout", function (d) { if(d.entity == "company")
{
d3.select(this).attr("width", "70px")
.attr("x", "-36px")
.attr("y", "-36px")
.attr("xlink:href", function(d){ return d.img_hrefD});
}
});
node.append("text")
.attr("class", function(d){ return "nodetext title_"+d.name })
.attr("dx", 0)
.attr("dy", ".35em")
.style("font-size","10px")
.attr("text-anchor", "middle")
.style("fill", "white")
.text(function(d) { if (d.entity != "description"){return d.name} });
node.on("mouseover", function (d) {
if (d.entity == "company"){
d3.select(this).select('text')
.transition()
.duration(300)
.text(function(d){
return d.full_name;
})
.style("font-size","15px")
}
else if(d.entity == "employee"){
var asdf = d3.select(this);
asdf.select('text').remove();
asdf.append("text")
.text(function(d){return d.prefix + ' ' + d.fst_name })
.attr("class","nodetext")
.attr("dx", 0)
.attr("dy", ".35em")
.style("font-size","5px")
.attr("text-anchor", "middle")
.style("fill", "white")
.transition()
.duration(300)
.style("font-size","12px");
asdf.append("text").text(function(d){return d.snd_name })
.attr("class","nodetext")
.attr("transform","translate(0, 12)")
.attr("dx", 0)
.attr("dy", ".35em")
.style("font-size","5px")
.attr("text-anchor", "middle")
.style("fill", "white")
.transition()
.duration(300)
.style("font-size","12px");
}
else {
d3.select(this).select('text')
.transition()
.duration(300)
.style("font-size","15px")
}
if (d.entity == "company") {
d3.select(this).select('image')
.attr("width", "90px")
.attr("x", "-46px")
.attr("y", "-36.5px")
.attr("xlink:href", function (d) {
return d.img_hrefL
});
}
if (d.entity == "company") {
d3.select(this).select('circle')
.transition()
.duration(300)
.attr("r",28)
}
else if (d.entity == "employee"){
d3.select(this).select('circle')
.transition()
.duration(300)
.attr("r",32)
}
})
node.on("mouseout", function (d) {
if (d.entity == "company") {
d3.select(this).select('text')
.transition()
.duration(300)
.text(function(d){return d.name;})
.style("font-size","10px")
}
else if(d.entity == "employee"){
///////////////////////////
// CHANGE
///////////////////////////
d3.select(this).selectAll('text').remove();
//d3.select(this).select('text')
d3.select(this).append('text')
.text(function(d){return d.name;})
.style("font-size","14px")
.attr("dx", 0)
.attr("dy", ".35em")
.attr("text-anchor", "middle")
.style("fill", "white")
.attr("class","nodetext")
.transition()
.duration(300)
.style("font-size","10px")
}
else {
d3.select(this).select('text')
.transition()
.duration(300)
.style("font-size","10px")
}
if (d.entity == "company") {
d3.select(this).select('image')
.attr("width", "70px")
.attr("x", "-36px")
.attr("y", "-36px")
.attr("xlink:href", function (d) {
return d.img_hrefD
});
}
if (d.entity == "company" || d.entity == "employee") {
d3.select(this).select('circle')
.transition()
.duration(300)
.attr("r",18)
}
});
force.on("tick", function() {
link.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; });
node.attr("transform", function(d) { return "translate(" + d.x + "," + d.y + ")"; });
linkcirc.attr("cy", function(d) { return d.target.y; })
.attr("cx", function(d) { return d.source.x+60; })
});
//});
最佳答案
只需将坐标相加并除以 2 即可得到中心位置:
linkcirc
.attr("cy", function(d) { return (d.source.y + d.target.y)/2; })
.attr("cx", function(d) { return (d.source.x + d.target.x)/2; });
更新了 jsfiddle here .
关于javascript - d3js 在力有向图中的线元素上附加圆形形状？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/19134831/