javascript - 基于页面标题/位置的重定向

Question

我正在尝试将我的在线帮助重定向到手机版本。但是，我从单一来源生成电话和桌面版本，因此我希望有一段代码可以分别执行此操作(电话 <-769-> 桌面)。由于大小发生，我使用以下方法进行了重定向:

if (screen.width <= 769 || windowWidth <= 769) {
window.location = "../phone/Selecting_a_School_Register.htm";

但是当我在电话页面上时，它一直尝试加载页面(我明白为什么)。我自己尝试过，但我对此很陌生，这是我的(失败的)尝试:

windowWidth = window.innerWidth;
<!--
if (location.pathname = "/desktop/Selecting_a_School_Register.htm";) 
{
} else if (screen.width <= 769 || windowWidth <= 769) {
window.location = "../phone/Selecting_a_School_Register.htm";

}
</script><script>
if (location.pathname = "/phone/Selecting_a_School_Register.htm";) 
{
} else if (screen.width >= 769 || windowWidth >= 769) {
window.location = "../desktop/Selecting_a_School_Register.htm";

}

Answer 1

任何类型的条件语句都需要两个“==”，而不是像代码示例所示的单个“=”。另外，您的 if 语句中的字符串后面不需要分号。

比双等号更好的是三等号，即 strict comparison operator

试试这个:

windowWidth = window.innerWidth;

if (location.pathname === "/desktop/Selecting_a_School_Register.htm") {
} 
else if (screen.width <= 769 || windowWidth <= 769) {
    window.location = "../phone/Selecting_a_School_Register.htm";
}

if (location.pathname === "/phone/Selecting_a_School_Register.htm") {
} 
else if (screen.width >= 769 || windowWidth >= 769) {
    window.location = "../desktop/Selecting_a_School_Register.htm";
}

编辑:

此代码完全满足您的需要:

var pathname = window.location.pathname
  , width = window.innerWidth || document.documentElement.clientWidth || document.getElementsByTagName('body')[0].clientWidth;

if (width <= 769 && pathname !== '/mobile.html') {
    window.location = '/mobile.html';
}

if (width > 769 && pathname !== '/desktop.html') {
    window.location = '/desktop.html';
}