javascript - YouTube API 查询返回 null

标签 javascript youtube youtube-api google-api google-api-client

YouTube 搜索查询“Kanye West Amazing”应该返回几个 YouTube 链接。但是,通过 api 进行的 youtube 查询返回 null(来自 console.log):

<!doctype html>
<html>
  <head>
    <title>Vidify</title>
  </head>

  <body>
    <!--Add a button for the user to click to initiate auth sequence -->
    <button id="authorize-button" style="visibility: hidden">Authorize</button>
    <script type="text/javascript">

      var clientId = '591751286145-ktngvf2s76uiuuevan6mo1fft0kchl8l.apps.googleusercontent.com';

      var apiKey = 'AIzaSyB0mteDV5vDKFR-iAv4Fx4OC2gp1Yhqe9U';

      var scopes = 'https://www.googleapis.com/auth/youtube';

      function handleClientLoad() {
        console.log('API key provided - authorizing client...');
        // Step 2: Reference the API key
        gapi.client.setApiKey(apiKey);
        gapi.auth.init(checkAuth);
      }

      function checkAuth() {
        console.log('entered checkAuth - authorizing...');
        setTimeout(function() { 
            console.log("requesting auth");
            gapi.auth.authorize({ 
                client_id: clientId, 
                scope: scopes, 
                response_type:'token',
                immediate: true 
            }, handleAuthResult); 
        }, 100); 
      }

      function handleAuthResult(authResult) {
        console.log('received authResult');
        var authorizeButton = document.getElementById('authorize-button');
        if (authResult && !authResult.error) {
          console.log("auth. successful");
          authorizeButton.style.visibility = 'hidden';
          makeApiCall();
        } else {
          console.log('auth failed.');
          authorizeButton.style.visibility = '';
          authorizeButton.onclick = handleAuthClick;
        }
      }

      function handleAuthClick(event) {
        // Step 3: get authorization to use private data
        console.log('retry');
        gapi.auth.authorize({client_id: clientId, scope: scopes, immediate: false}, handleAuthResult);
        return false;

      }

      // Load the API and make an API call.  Display the results on the screen.
        function makeApiCall() {
            console.log("loaded client");
            gapi.client.setApiKey(apiKey);
            // Step 4: Load the Google+ API
            gapi.client.load('youtube', 'v3', function() {
                console.log('youtube API loaded...');
                // Step 5: Assemble the API request
                var qVar = "Kanye West Amazing"
                // changed. added: type
                var request = gapi.client.youtube.search.list({
                    type: 'video',
                    part: 'id',
                    q: qVar
                });
                // Step 6: Execute the API request
                request.execute(function(resp) {

                    console.log(resp);
                    var vid = document.createElement('vid');
                    vid.value = resp.items[0].id.videoId;
                    console.log(vid.value);
                    var youtube_url = "http://www.youtube.com/watch?v=";
                    youtube_url += vid.value;
                    youtube_url += "&rel=0";
                    window.open(youtube_url);
                });
              });
          }
    </script>

    <script src="https://apis.google.com/js/client.js?onload=makeApiCall"></script>

  </body>
</html>

所以我实际上正在尝试从 Spotify 桌面应用程序中运行它。 Spotify 应用程序系统允许我从“spotify 浏览器”中加载 index.html。以下是我现在遇到的错误:

Uncaught TypeError: Cannot call method 'setApiKey' of undefined

index.html:63 makeApiCall index.html:63 (anonymous function)

client.js?onload=makeApiCall:6 fa client.js?onload=makeApiCall:1 b

client.js?onload=makeApiCall:6 v.(anonymous function)

client.js?onload=makeApiCall:6 H.(anonymous function)

client.js?onload=makeApiCall:6 (anonymous function) cb=gapi.loaded_0:1

Uncaught TypeError: Cannot read property 'prototype' of undefined cb=gapi.loaded_0:6

_.J cb=gapi.loaded_0:6 (anonymous function) cb=gapi.loaded_1:6 (anonymous function) client.js?onload=makeApiCall:4 Z

client.js?onload=makeApiCall:6 ua client.js?onload=makeApiCall:4 E

client.js?onload=makeApiCall:5 b client.js?onload=makeApiCall:6

v.(anonymous function) client.js?onload=makeApiCall:6 H.(anonymous function) client.js?onload=makeApiCall:6 (anonymous function) cb=gapi.loaded_1:1

最佳答案

看来您的嵌套可能不正确;您正在gapi.client.load函数的回调之外运行request.execute调用,因此当它尝试运行时,实际的请求本身不会被创建(gapi客户端异步加载API)。如果您尝试这样做:

  function makeApiCall() {
    // Step 4: Load the Google+ API
    gapi.client.load('youtube', 'v3', function() {
        console.log('youtube API loaded...');
        // Step 5: Assemble the API request
        var qVar = "Kanye West Amazing"
        // changed. added: type
        var request = gapi.client.youtube.search.list({
            type: 'video',
            part: 'id',
            q: qVar
        });
        // Step 6: Execute the API request
        request.execute(function(resp) {
          document.getElementById('vid').value = resp.items[1].id.videoId;
          console.log('saved video id successfully');
        });
      });
  }

然后它应该等待并仅在 API 代码加载后才执行请求。当然,这还假设您有一个 id 为“vid”的元素(您的示例代码没有)。

就范围而言,您不需要它们来执行此特定调用,因为它不需要进行身份验证(即您可以在未经授权的情况下运行 MakeApiCall() )。但是,如果您稍后要做其他需要授权的事情,它会正常工作,因此您可以轻松地将其保留。

关于javascript - YouTube API 查询返回 null,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20864312/

相关文章:

javascript - 具有多列数据的凹痕多行

video - UIWebView iPhone OS 4.0无法查看YouTube视频

javascript - 如何在 youtube 章节标记播放器的章节菜单上播放视频时突出显示当前章节

javascript - Ngx-Bootstrap Typeahead 在输入清除时保留下拉值

javascript - 如何将字符串化的正则表达式文字转换回正则表达式?

javascript - 如何在 Facebook 帖子中嵌入自定义 HTML5 播放器?

android - Android:如何检索YouTube搜索结果及其视频ID?

android - 如何将 youtube playerview 与 scrollview 一起使用?

java - 如何正确应用 yt :accessControl in YouTube-API Java

Javascript 从当前目录读取文本文件