php - 如何进一步过滤mysql中的GROUP BY记录？

Question

请检查我想要查询 ID“43”的完整行(以及另一个 nic_id max query_id 行)的图像，但它只给我最大 query_id，我尝试了不同的查询，例如:

SELECT `Query_id`, `nic_id`, `date`, `subject`, `followup_no`, MAX(Query_id) as queryid FROM `sales_queries` GROUP BY `nic_id` HAVING MAX(`Query_id`)

SELECT `Query_id`, `nic_id`, `date`, `subject`, `followup_no`, MAX(Query_id) as queryid FROM `sales_queries` WHERE  GROUP BY `nic_id` HAVING MAX(`Query_id`)

SELECT  `Query_id`, `nic_id`, `date`, `subject`, `followup_no`, MAX(Query_id) as mxqueryid    FROM `sales_queries`WHERE `Query_id` = (SELECT MAX(`Query_id`) FROM `sales_queries`) GROUP BY `nic_id` 

当客户再次访问时，使用不同主题的相同 nic_id 进行跟进增加 (+1)。

我想要完整的 43 行，主题为“Registration4”，日期等

不是这个，应该是 Registration4 date:2015-09-11

Answer 1

类似于this question的答案，您可以使用子查询并加入以获取您想要的结果。类似于以下的内容应该可以工作:

SELECT `Query_id`, `nic_id`, `date`, `subject`, `followup_no`
FROM `sales_queries` AS sq
INNER JOIN (
    SELECT MAX(`Query_id`) AS mId
    FROM `sales_queries`
    GROUP BY `nic_id`
) AS subsq ON subsq.mId = sq.Query_id