javascript - 从 php 中的 html 获取值

Question

如何从php中的html中获取值？我怎样才能改变“.$x”。在 php 中得到的结果是 JavaScript 中的 var click 。目前，它仅显示值“.x”。当我点击下一步按钮时。

php文件

<?php

$con=mysqli_connect("localhost","root","password","DB");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$x = 1;

$sql="select * from sentence where id = ".$x." limit 10";

if ($result=mysqli_query($con,$sql))
{
 // Fetch one and one row
while ($row=mysqli_fetch_row($result))
{
$output = $row[1];
}
 // Free result set
 mysqli_free_result($result);
}

mysqli_close($con);
?>

Javascript

function next() {

if(typeof(Storage) !== "undefined") {
    if (sessionStorage.clickcount) {
        sessionStorage.clickcount = Number(sessionStorage.clickcount)+1;
    } else {
        sessionStorage.clickcount = 1;
    }
    document.getElementById("result").innerHTML =  sessionStorage.clickcount;
} else {
    document.getElementById("result").innerHTML = "Sorry, your browser does not support web     
storage...";
}

}
var click = sessionStorage.clickcount;

function nextnext(){
alert(click);
}

HTML

 <center><button onclick='next()'>NEXT</button></center>
 <div id="result"></div>

Answer 1

您需要使用 post/get 或 ajax 调用将值从客户端(用你的话说 - html)发送到 php 你的问题不清楚。 如果以下内容不是您所期望的，请告诉我。我会更正答案 试试这个:

<form method="GET" action="urPHPFIle.php">
<input type="hidden" value="x_value" name="x" />
<input type="click" value="send" />
</form>

单击上面的 $_GET['x'] 值将等于 x_Value 或您在输入的 value 属性中输入的值

<?php

$con=mysqli_connect("localhost","root","password","DB");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$x = 1;

$sql="select * from sentence where id = ".$_GET['x']." limit 10";

if ($result=mysqli_query($con,$sql))
{
 // Fetch one and one row
while ($row=mysqli_fetch_row($result))
{
$output = $row[1];
}
 // Free result set
 mysqli_free_result($result);
}

mysqli_close($con);
?>