我想应用取决于州和城市的下拉菜单。我的问题是，当我选择州时，城市下拉列表不显示任何值。
我的数据库在这里(状态表)
id 州名 1 议员 2 起
id 州索引 城市名称 1 1 博帕尔 2 1 印多尔 3 2 帕特纳
我的 Controller 在这里(main_controller)
<?php
class Main_controller extends CI_Controller {
function index()
{
$this->load->model('model_form');
$this->data['states'] = $this->model_form->get_state();
$this->load->view('view_form_all',$this->data);
}
function get_cities($state){
$this->load->model('Model_form','', TRUE);
header('Content-Type: application/x-json; charset=utf-8');
echo(json_encode($this->Model_form->get_cities_by_state($state)));
}
}
我的模型是(main_form.php)
<?php
class Model_form extends CI_Model
{
function __construct()
{
// Call the Model constructor
parent::__construct();
}
function get_state(){
$query = $this->db->query('SELECT id, state_name FROM state');
return $query->result();
}
function get_cities_by_state ($state, $tree = null){
$this->db->select('id, city_name');
if($tree != NULL){
$this->db->where('state_index', $state);
}
$query = $this->db->get('cities');
$cities = array();
if($query->result()){
foreach ($query->result() as $city) {
$cities[$city->id] = $city->city_name;
}
return $cities;
} else {
return FALSE;
}
}
}
我的观点是(view_from_all.php)
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Untitled Document</title>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js" type="text/javascript"></script>
<script type="text/javascript">
$('#f_city, #f_city_label').hide();
$('#f_state').change(function(){
alert('f_state');
var state_id = $('#f_state').val();
if (state_id != ""){
var post_url = "<?php echo base_url();?>index.php/main_controller/get_cities/" + state_id;
$.ajax({
type: "POST",
url: post_url,
success: function(cities) //we're calling the response json array 'cities'
{
$('#f_city').empty();
$('#f_city, #f_city_label').show();
$.each(cities,function(id,city)
{
var opt = $('<option />'); // here we're creating a new select option for each group
opt.val(id);
opt.text(city);
$('#f_city').append(opt);
});
} //end success
}); //end AJAX
} else {
$('#f_city').empty();
$('#f_city, #f_city_label').hide();
}//end if
}); //end change
</script>
</head>
<body>
<?php echo form_open('main_controller/add_all'); ?>
<label for="f_state">State<span class="red">*</span></label>
<select id="f_state" name="f_state">
<option value="">select any state</option>
<?php
foreach($states as $state){
echo '<option value="' . $state->id . '">' . $state->state_name . '</option>';
}
?>
</select>
<label for="f_city">City<span class="red">*</span></label>
<!--this will be filled based on the tree selection above-->
<select id="f_city" name="f_city" id="f_city_label">
<option value=""></option>
</select>
<label for="f_membername">Member Name<span class="red">*</span></label>
<!--<input type="text" name="f_membername"/>-->
<?php echo form_close(); ?>
</body>
</html>
最佳答案
尝试 GET 而不是 POST，因为如果您激活了 CSRF 保护，您在发送请求时会遇到问题，提示您的 token 丢失，因此只需更改此即可:
$.ajax({
type: "POST",
对此:
$.ajax({
type: "GET",
其他有趣的改变:
header('Content-Type: application/x-json; charset=utf-8');
echo(json_encode($this->Model_form->get_cities_by_state($state)));
至:
$result = $this->Model_form->get_cities_by_state($state);
return $this->output->set_content_type('application/json')
->set_output(json_encode($result));
关于javascript - 如何在 codeigniter 中创建依赖下拉菜单，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/27654112/