php - 如何根据纬度和经度应用过滤器？

Question

我想根据纬度和经度应用过滤器。有一个表，其中包含列 id、标题、纬度、经度 (MySql)，我想获得 4 公里范围内的结果，因为我提供了当前位置的纬度和经度。

SELECT * FROM ads WHERE (latitude = 26.85005 AND longitude = 26.85393) AND (longitude = 80.94964 AND longitude = 80.96595) HAVING acos(sin(1.3963) * sin(latitude) + cos(1.3963) * cos(latitude) * cos(longitude - (-0.6981))) <= 0.1570 

Answer 1

是的，这是可能的。

SELECT a.title,
   111.111 *
    DEGREES(ACOS(LEAST(COS(RADIANS(a.Latitude))
         * COS(RADIANS(b.Latitude))
         * COS(RADIANS(a.Longitude - b.Longitude))
         + SIN(RADIANS(a.Latitude))
         * SIN(RADIANS(b.Latitude)), 1.0))) AS distance_in_km
  FROM table AS a
  JOIN table AS b ON a.id <> b.id
  HAVING distance_in_km <= 4

在这里，HAVING distance_in_km <= 4 4是KM范围。