我想在一个查询中组合三个表 - 日期、潜在客户和点击。
表格如下所示:
日期:
|date|
铅:
id|time|commission
点击:
id|time|commission
表格日期只是存储日期,在没有点击或引导的情况下获取日期时使用。
所以如果我们在表中有以下数据:
日期:
2009-06-01
2009-06-02
2009-06-03
铅:
1|2009-06-01|400
2|2009-06-01|300
3|2009-06-03|350
点击:
1|2009-06-01|1
2|2009-06-03|2
3|2009-06-03|2
4|2009-06-03|0
我想获取日期、点击次数、点击产生的佣金(有些点击不给佣金)、潜在客户数量、潜在客户产生的佣金和总佣金。因此,对于上面的表格,我想得到:
2009-06-01|1|1|2|700|701|
2009-06-02|0|0|0|0|0
2009-06-03|3|4|1|350|354|
我尝试过以下联合:
SELECT
campaign_id,
commission_date,
SUM( click_commission ) AS click_commission,
click,
SUM( lead_commission ) AS lead_commission ,
lead,
SUM( total_commission ) as total_commission
FROM(
SELECT
click.campaign_id AS campaign_id,
DATE( click.time ) AS commission_date,
click.commission AS click_commission,
(SELECT count(click.id) from click GROUP BY date(click.time)) as click,
0 as lead_commission,
0 as lead,
click.commission AS total_commission
FROM click
UNION ALL
SELECT
lead.campaign_id AS campaign_id,
DATE( lead.time ) AS commission_date,
0 as click_commission,
0 as click,
lead.commission AS lead_commission,
lead.id as lead,
lead.commission AS total_commission
FROM lead
UNION ALL
SELECT
0 AS campaign_id,
date.date AS commission_date,
0 AS click_commission,
0 as click,
0 AS lead_commission,
0 as lead,
0 AS total_commission
FROM date
) AS foo
WHERE commission_date BETWEEN '2009-06-01' AND '2009-07-25'
GROUP BY commission_date
ORDER BY commission_date LIMIT 0, 10
但这并不能同时计算点击次数和潜在客户数量,上面的代码在所有潜在客户上给出了正确的点击量 bot 0。如果我四处移动代码并从潜在客户表中进行选择,我会在所有点击中获得正确的潜在客户机器人 0。我一直无法找到一种方法来从查询中获取这两个计数。
所以我尝试了左连接:
SELECT
date.date as date,
count( DISTINCT click.id ) AS clicks,
sum(click.commission) AS click_commission,
count( lead.id ) AS leads,
sum(lead.commission) AS lead_commission
FROM date
LEFT JOIN click ON ( date.date = date( click.time ) )
LEFT JOIN lead ON ( date.date = date( lead.time ) )
GROUP BY date.date
LIMIT 0 , 30
此查询的问题是,如果在某个日期有多次点击或潜在客户,它将返回预期值 * 2。因此,在 2009 年 6 月 1 日,它将返回 1400,而不是潜在客户佣金的预期 700。
所以在 UNION 中,我的计数有问题,在左连接中,SUM 不起作用。
如果可能的话,我真的很想坚持使用 UNION,但我还没有找到从中获得这两个计数的方法。
(这是对 this 较早问题的跟进,但由于我没有要求其中的计数,所以我发布了一个新问题。)
最佳答案
SELECT date,
COALESCE(lcomm, 0), COALESCE(lcnt, 0),
COALESCE(ccomm, 0), COALESCE(ccnt, 0),
COALESCE(ccomm, 0) + COALESCE(lcomm, 0),
COALESCE(ccnt, 0) + COALESCE(lcnt, 0)
LEFT JOIN
(
SELECT date, SUM(commission) AS lcomm, COUNT(*) AS lcnt
FROM leads
GROUP BY
date
) l
ON l.date = d.date
LEFT JOIN
(
SELECT date, SUM(commission) AS ccomm, COUNT(*) AS ccnt
FROM clicks
GROUP BY
date
) с
ON c.date = d.date
FROM date d
关于mysql - 与 Count 合并或与 Sum 合并 - MySQL,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/1099040/