javascript - 验证 'Price'( double )表单输入 PHP

Question

您好，我正在尝试使用 PHP 验证表单上的用户输入。 我已成功验证文本、数字和年份输入，但无法获取价格。

我在代码顶部创建错误变量:

 $titleErr = ""; $developerErr = ""; $releaseErr = ""; $stockErr = ""; $priceErr = "";

然后，我验证输入并根据需要向变量分配一条消息:

if (!preg_match("/^[a-zA-Z ]*$/",$title)) {
                    $titleErr = "Invalid input, only letters and white space allowed.";
                } else if (!preg_match("/^[a-zA-Z ]*$/",$developer)){
                    $developerErr = "Invalid input, only letters and white space allowed.";
                } else if ($release<1990 || $release>2020){
                    $releaseErr = "Invalid input, enter a year between 1990 & 2020.";
                } else if (!is_numeric($stock)){
                    $stockErr = "Invalid input, only numbers allowed.";
                } else if (!is_float($price)){
                    $priceErr = "Invalid input, only doubles allowed.";
                }

前 4 条语句完美地验证了输入。然而，当我输入正确的输入时，最后一个检查输入是否为 float (价格例如 10.99)似乎会返回错误消息。

这是我的表格:

<form class ="form-horizontal" role="form" id="add" name="add" action="?" method="post">           
            <div class="form-group">
                <label class="control-label col-sm-2">Title</label> <div class="col-sm-10"><input class="form-control" id="addFormTitle" name="title" type="text"> <span class="error"><?php echo $titleErr;?></span></div>
            </div>
            <div class="form-group">
                <label class="control-label col-sm-2">Developer</label> <div class="col-sm-10"><input class="form-control" id="addFormDeveloper" name="developer" type="text"> <span class="error"><?php echo $developerErr;?></span></div>
            </div>
            <div class="form-group">
                <label class="control-label col-sm-2">Release (Year Format/YYYY)</label> <div class="col-sm-10"><input class="form-control" id="addFormRelease" name="release" type="text"> <span class="error"><?php echo $releaseErr;?></span></div>
            </div>
            <div class="form-group">
                <label class="control-label col-sm-2">Stock</label> <div class="col-sm-10"><input class="form-control" id="addFormStock" name="stock" type="text"> <span class="error"><?php echo $stockErr;?></span></div>
            </div>
            <div class="form-group">
                <label class="control-label col-sm-2">Price (&#163)</label> <div class="col-sm-10"><input class="form-control" id="addFormPrice" name="price" type="text"> <span class="error"><?php echo $priceErr;?></span></div>
            </div>
            <div class="form-group">
                <div class="col-sm-offset-2 col-sm-10">
                    <button type="submit" class="btn btn-default" name="addSubmit" value="Add product">Submit</button>
                </div>
            </div>
        </form>

Answer 1

您可以使用floatval函数获取变量的浮点值，然后检查它是否为浮点值，如下所示:

if(is_float(floatval($price))){
    echo "float value";
}else{
    echo "not a float value";
}

已编辑:

在您的代码中，您可以执行以下操作:

if (!preg_match("/^[a-zA-Z ]*$/",$title)) {
    $titleErr = "Invalid input, only letters and white space allowed.";
} else if (!preg_match("/^[a-zA-Z ]*$/",$developer)){
    $developerErr = "Invalid input, only letters and white space allowed.";
} else if ($release<1990 || $release>2020){
    $releaseErr = "Invalid input, enter a year between 1990 & 2020.";
} else if (!is_numeric($stock)){
    $stockErr = "Invalid input, only numbers allowed.";
} else if (!is_float(floatval($price))){
    $priceErr = "Invalid input, only doubles allowed.";
}