此代码可以与下面给出的 JSON data1 对象一起正常工作,但我希望此代码可以与此 new_json 对象一起使用。我想在节点 id 上建立链接。有什么帮助吗?
var new_json = {{"nodes": [{ "id": 124587, "name": "paper1", "citation": 5, "group": 1 },
{ "id": 178456, "name": "paper2", "citation": 8, "group": 2 }],
"links": [{ "source": 124587, "target": 178456, "name": "A-B-1", "value": 8 }]};
function load_graph(text) {
var color = d3.scale.category20();
var data1 = {
"nodes": [
{ "id": 0, "name": "paper1", "citation": 5, "group": 1 },
{ "id": 1, "name": "paper2", "citation": 8, "group": 2 },
{ "id": 2, "name": "paper3", "citation": 12, "group": 3 },
{ "id": 3, "name": "paper4", "citation": 25, "group": 4 },
{ "id": 4, "name": "paper5", "citation": 15, "group": 5 },
{ "id": 5, "name": "paper6", "citation": 5, "group": 1 },
{ "id": 6, "name": "paper7", "citation": 8, "group": 2 },
{ "id": 7, "name": "paper8", "citation": 12, "group": 3 },
{ "id": 8, "name": "paper9", "citation": 25, "group": 4 },
{ "id": 9, "name": "paper10", "citation": 15, "group": 5 }
],
"links": [
{ "source": 0, "target": 1, "name": "A-B-1", "value": 8 },
{ "source": 0, "target": 1, "name": "A-B-2", "value": 24 },
{ "source": 0, "target": 2, "name": "A-C-1", "value": 12 },
{ "source": 0, "target": 2, "name": "A-C-3", "value": 44 },
{ "source": 2, "target": 3, "name": "A-D-1", "value": 11 },
{ "source": 2, "target": 3, "name": "A-D-2", "value": 35 },
{ "source": 2, "target": 4, "name": "A-E-1", "value": 16 },
{ "source": 2, "target": 4, "name": "A-E-5", "value": 30 },
{ "source": 4, "target": 5, "name": "A-B-1", "value": 8 },
{ "source": 4, "target": 5, "name": "A-B-2", "value": 24 },
{ "source": 5, "target": 6, "name": "A-C-1", "value": 12 },
{ "source": 5, "target": 6, "name": "A-C-3", "value": 44 },
{ "source": 5, "target": 7, "name": "A-D-1", "value": 11 },
{ "source": 5, "target": 7, "name": "A-D-2", "value": 35 },
{ "source": 7, "target": 8, "name": "A-E-1", "value": 16 },
{ "source": 7, "target": 8, "name": "A-E-5", "value": 30 },
{ "source": 8, "target": 3, "name": "A-C-1", "value": 12 },
{ "source": 8, "target": 3, "name": "A-C-3", "value": 44 },
{ "source": 8, "target": 9, "name": "A-D-1", "value": 11 },
{ "source": 8, "target": 9, "name": "A-D-2", "value": 35 }
]
};
// used to store the number of links between two nodes.
// mLinkNum[data.links[i].source + "," + data.links[i].target] = data.links[i].linkindex;
var mLinkNum = {};
// sort links first
sortLinks();
// set up linkIndex and linkNumer, because it may possible multiple links share the same source and target node
setLinkIndexAndNum();
var w = 960,
h = 500;
var force = d3.layout.force()
.nodes(d3.values(data1.nodes))
.links(data1.links)
.size([w, h])
.linkDistance(200)
.charge(-300)
.on("tick", tick)
.start();
var svg = d3.select(".graphContainer").append("svg:svg")
.attr("width", w)
.attr("height", h);
var path = svg.append("svg:g")
.selectAll("line")
.data(force.links())
.enter().append("svg:path")
.attr("class", "link")
.style("stroke-width", function (d) { return Math.sqrt(d.value); });
var circle = svg.append("svg:g")
.selectAll("circle")
.data(force.nodes())
.enter().append("svg:circle")
.attr("r", function (d) { return (d.citation); })
.style("fill", function (d) { return color(d.group); })
.call(force.drag);
var text = svg.append("svg:g")
.selectAll("g")
.data(force.nodes())
.enter().append("svg:g");
// A copy of the text with a thick white stroke for legibility.
text.append("svg:text")
.attr("x", 8)
.attr("y", ".31em")
.attr("class", "shadow")
.text(function (d) { return d.name; });
text.append("svg:text")
.attr("x", 8)
.attr("y", ".31em")
.text(function (d) { return d.name; });
// Use elliptical arc path segments to doubly-encode directionality.
function tick() {
path.attr("d", function (d) {
var dx = d.target.x - d.source.x,
dy = d.target.y - d.source.y,
dr = Math.sqrt(dx * dx + dy * dy);
// get the total link numbers between source and target node
var lTotalLinkNum = mLinkNum[d.source.id + "," + d.target.id] || mLinkNum[d.target.id + "," + d.source.id];
if (lTotalLinkNum > 1) {
// if there are multiple links between these two nodes, we need generate different dr for each path
dr = dr / (1 + (1 / lTotalLinkNum) * (d.linkindex - 1));
}
// generate svg path
return "M" + d.source.x + "," + d.source.y +
"A" + dr + "," + dr + " 0 0 1," + d.target.x + "," + d.target.y +
"A" + dr + "," + dr + " 0 0 0," + d.source.x + "," + d.source.y;
});
// Add tooltip to the connection path
path.append("svg:title")
.text(function (d, i) { return d.name; });
circle.attr("transform", function (d) {
return "translate(" + d.x + "," + d.y + ")";
});
text.attr("transform", function (d) {
return "translate(" + d.x + "," + d.y + ")";
});
}
// sort the links by source, then target
function sortLinks() {
data.links.sort(function (a, b) {
if (a.source > b.source) {
return 1;
}
else if (a.source < b.source) {
return -1;
}
else {
if (a.target > b.target) {
return 1;
}
if (a.target < b.target) {
return -1;
}
else {
return 0;
}
}
});
}
//any links with duplicate source and target get an incremented 'linknum'
function setLinkIndexAndNum() {
for (var i = 0; i < data.links.length; i++) {
if (i != 0 &&
data.links[i].source == data.links[i - 1].source &&
data.links[i].target == data.links[i - 1].target) {
data.links[i].linkindex = data.links[i - 1].linkindex + 1;
}
else {
data.links[i].linkindex = 1;
}
// save the total number of links between two nodes
if (mLinkNum[data.links[i].target + "," + data.links[i].source] !== undefined) {
mLinkNum[data.links[i].target + "," + data.links[i].source] = data.links[i].linkindex;
}
else {
mLinkNum[data.links[i].source + "," + data.links[i].target] = data.links[i].linkindex;
}
}
}
}
</script>
最佳答案
基本上,强制布局是根据索引而不是 id 或名称来工作的。所以你必须明确说明你想在你的情况下通过 id 链接:
var edges = [];
data.links.forEach(function(e) {
var sourceNode = data.nodes.filter(function(n) {
return n.id === e.source;
})[0],
targetNode = data.nodes.filter(function(n) {
return n.id === e.target;
})[0];
edges.push({
source: sourceNode,
target: targetNode
});
});
上面的代码检查哪个节点与链接 Source 具有相同的 id,然后将其插入 Edges 数组的源中,并且对于目标也相同。然后使用此边数组创建图形:
力量:
force
.nodes(data.nodes)
.links(edges)
对于链接:
var link = svg.selectAll(".link")
.data(edges)
这是我用您的 new_json
实现的 fiddle :https://jsfiddle.net/thatOneGuy/60oLwg8t/1/
或者在这里:
var data =
{
"nodes": [{
"id": 124587,
"name": "paper1",
"citation": 5,
"group": 1
}, {
"id": 178456,
"name": "paper2",
"citation": 8,
"group": 2
}],
"links": [{
"source": 124587,
"target": 178456,
"name": "A-B-1",
"value": 8
}]
};
console.log(data.nodes)
console.log(data.links)
var width = 960,
height = 500;
var color = d3.scale.category20();
var force = d3.layout.force()
.charge(-120)
.linkDistance(30)
.size([width, height]);
var svg = d3.select("body").append("svg")
.attr("width", width)
.attr("height", height);
var edges = [];
data.links.forEach(function(e) {
var sourceNode = data.nodes.filter(function(n) {
return n.id === e.source;
})[0],
targetNode = data.nodes.filter(function(n) {
return n.id === e.target;
})[0];
edges.push({
source: sourceNode,
target: targetNode,
value: e.Value
});
});
force
.nodes(data.nodes)
.links(edges)
.start();
var link = svg.selectAll(".link")
.data(edges)
.enter().append("line")
.attr("class", "link")
.style("stroke-width", 2);
var node = svg.selectAll(".node")
.data(data.nodes)
.enter().append("circle")
.attr("class", "node")
.attr("r", 5)
.style("fill", 'red')
.call(force.drag);
node.append("title")
.text(function(d) {
return d.name;
});
force.on("tick", function() {
link.attr("x1", function(d) {
return d.source.x;
})
.attr("y1", function(d) {
return d.source.y;
})
.attr("x2", function(d) {
return d.target.x;
})
.attr("y2", function(d) {
return d.target.y;
});
node.attr("cx", function(d) {
return d.x;
})
.attr("cy", function(d) {
return d.y;
});
});
.node {
stroke: #fff;
stroke-width: 1.5px;
}
.link {
stroke: #999;
stroke-opacity: .6;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/3.4.11/d3.min.js"></script>
关于javascript - 如何根据d3.js图形库中的节点id连接边与节点,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37031299/