我在将错误消息返回到注册表中时遇到问题:我有 2 个文件(register.php 和 process_register.php)， 实际上，在 register.php 中，我通过 POST 传递请求，而在 process_login 中执行一个函数 (register($conn,$username,$password))
这是文件的代码
process_register.php
<?php
if((include 'db_connect.php')==TRUE){echo"OKDB";}
if((include 'functions.php')==TRUE){echo"OKFUNCTIONS";}
sec_session_start();
if(login_check($conn) == true) //Already Logged In!
header('Location: ./index.php');
else{
if(isset($_POST['username'], $_POST['password'])) {
//Got username and pswd
$username=$_POST['username'];
$password = $_POST['password'];
$registerresult=register($conn,$username,$password);
if($registerresult==TRUE) //Registration success!
header('location: login.php');
else
header('location: register.php');
}else {
// Not here with a post request.
echo 'Invalid Request';
}
}
?>
注册($conn,$用户名,$密码)
function register($conn,$username,$password){
//ifusernamealreadyused
$alreadyregister="SELECT * FROM User WHERE username='$username';";
$query_alreadyregister=mysqli_query($conn,$alreadyregister);
$alreadyregister_rows=mysqli_num_rows($query_alreadyregister);
if($alreadyregister_rows!=0) //UsernameAlreadyUsed
return false;
else{ //UsernameNotAlreadyUsed
//RegistrationOK!
$registration="INSERT INTO User(username,password) VALUES('$username',sha2('$password',512));";
$query_registration=mysqli_query($conn,$registration);
return true;
}//UsernameNotAlreadyUsed
} //Register
我的问题是:如果用户名不“正确”，我如何在表单中显示消息？(返回 false) 提前干杯!
最佳答案
这非常简单，只需在现有代码中添加这些行即可
将此 header('location: register.php'); 更改为
header('location: register.php?message=username already exist');
并在您的register.php中检查此内容
<?php if(isset($_GET['message'])) {echo $_GET['message'];} ?>
关于javascript - PHP - 如何将错误消息返回到注册页面，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/37833811/