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EDIT START
所以我发现我的代码有问题。是下面这行
if(isset($_REQUEST['faq_submit'])) {
我不确定这条线有什么问题？为什么不能正常工作？
EDIT END
出于某种原因，我准备好的声明不起作用。此外，它似乎没有在错误日志中显示任何错误。现在我可能只是在那里做错了什么，但我相信这里有人能发现我做的错误哈哈……我尝试用几种不同的方式修复它，但没有成功，所以在这里寻求帮助总是一个不错的选择!
这是我添加问题的php代码
// Required Configuration
include_once('required.php');
// double check page was accessed via submit button
if(isset($_REQUEST['faq_submit'])) {
// get data that sent from form
$topic=trim($_REQUEST['faq_topic']);
$detail=trim($_REQUEST['faq_detail']);
$name=trim($_REQUEST['faq_name']);
$email=trim($_REQUEST['faq_email']);
// check if all forms are filled out
if(!empty($topic) && !empty($detail) && !empty($name) && !empty($email)) {
// Validate Email
if (filter_var($email, FILTER_VALIDATE_EMAIL)) {
// Prepared Insert Statement
$stmt = $mysqli->prepare('INSERT INTO forum_question (`topic`, `detail`, `name`, `email`, `datetime`) VALUES (?, ?, ?, ?, ?)');
// Bind Variables To Values
$stmt->bind_param('sssss', $topic, $detail, $name, $email, $datetime);
// Execute Prepared Statement
$stmt->execute();
// Print Results
$html = '<div class="alert alert-dismissable alert-success"><button type="button" class="close" data-dismiss="alert">×</button>You <strong>successfully</strong> submited a question to the FAQ bored.</div>';
print($html);
// Close Connections and Statement
$stmt->close(); // Statement
$mysqli->close(); // MySQLi
} else {
// Email Validation Failed
$html = '<div class="alert alert-dismissable alert-danger"><button type="button" class="close" data-dismiss="alert">×</button>Your <strong>email</strong> was invalid.</div>';
print($html);
}
} else {
// If the required items were not filled out print the following
$html = '<div class="alert alert-dismissable alert-danger"><button type="button" class="close" data-dismiss="alert">×</button><strong>All</strong> forms are required.</div>';
print($html);
}
}
这是 required.php 文件，尽管我删除了一些登录信息。
$datetime=date("m/d/y h:i"); // Format Date And Time
// Connect
$mysqli = new mysqli('host', 'user', 'pass', 'db');
// Check Connection
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}