php - mysql_query如何与一个 "dynamic"数据库一起使用呢？

Question

今天我在我的网站上工作，试图显示游戏的最后获胜者。这是我的代码:

 $lastgame = fetchinfo("value","info","name","current_game");

$winnercost = fetchinfo("cost","games","id",$lastgame-1);
$winnerpercent = round(fetchinfo("percent","games","id",$lastgame-1),1);
$winneravatar = fetchinfo("avatar","users","steamid",$lastwinner);
$winnername = fetchinfo("name","users","steamid",$lastwinner);



echo '<p>Game #'.$lastgame.'</p>'; 
echo '<p>'.$winnername.' won the jackpot</p>'; 
echo '<p> valued at '.$winnercost.'</p>'; 
echo '<p>with a winning chance of '.$winnerpercent.'</p>'; 

关键是我只使用 fetchinfo，所以它显示信息但不是实时的，我必须刷新我的页面才能显示最新的获胜者。我想我需要创建一个 mysql_query。

我的问题是我不明白如何使用 mysql_query，我知道每次获胜者获胜都会在我的表中创建一个新行。例如:

id : 1
startime :1441330544
total price : 3.17
Winner : Foxy
steam id : 76561198042016725
Percent chances to win : 98.7381703
Number of total item : 2
module : 0.24973750

谁有解决方案可以帮助我？这个-1

,$lastgame-1),1);

给我一​​些困难:(

网站atm上的结果:

游戏#4 狐狸中了大奖 值(value)3.31 获胜几率为 94.6

Answer 1

根据您提供的信息，我认为您可以使用的最简单的查询如下:

select * from <tblname> order by steamid desc limit 1;

对于自动刷新，您可以执行以下两项操作之一:

1) you could add: <meta http-equiv="refresh" content="5"> in the header of your html and the page will automatically refresh every 5 seconds.  (basic)

2) you could use ajax to make a call to execute the query and update the page which is a much nicer user experience (more advanced)