php - 在单个 mysql 列中插入动态字段输入

Question

下面代码的概念是允许用户通过收集每个输入并将它们发布到单独的列中来将多个输入字段输入到数据库中，如下面的代码片段所示。

我遇到的问题是，当我尝试插入代码时，它只会在 mysql 表中插入“数组”，因此我尝试使用 foreach($BX_NAME as $a => $b){ 的原因是什么？ > 现在它只输入最后一个输入而不是整个数组。在谷歌搜索和研究之后，我发现有一个名为 serialize() 的函数，但问题是它将整个数组发布到一个单独的列中，这有效..但我相信如果我单独插入每一列会更好。

任何有助于故障排除的帮助将不胜感激。

     $error = false;

     if ( isset($_POST['btn-signup']) ) {

      // clean user inputs to prevent sql injections


      $company_invoice = trim($_POST['company_invoice']);
      $company_invoice = strip_tags($company_invoice);
      $company_invoice = htmlspecialchars($company_invoice);

      $contact_name = trim($_POST['contact_name']);
      $payment_type = strip_tags($contact_name);
      $payment_type = htmlspecialchars($contact_name);

      $added_by = trim($_POST['added_by']);
      $added_by = strip_tags($added_by);
      $added_by = htmlspecialchars($added_by);

            $chkbox = $_POST['chk'];
            $BX_NAME=$_POST['BX_NAME'];
            $BX_PRICE_POST['BX_price'];     

       foreach($BX_NAME as $a => $b){ ?>

                    <?php echo $BX_NAME[$a]; ?>
                  <?php echo $BX_price[$a]; 
                }

      // if there's no error, continue to Registeration
      if( !$error ) {

       $query = "INSERT INTO company_invoices(company_name,contact_name,BX_NAME,BX_price,added_by,date_added) VALUES('$company_name','$contact_name','$BX_NAME[$a]','$BX_price[$a]', ' $added_by',now())";
       $res = mysql_query($query);

function addRow(tableID) {
	var table = document.getElementById(tableID);
	var rowCount = table.rows.length;
	if(rowCount < 5){							// limit the user from creating fields more than your limits
		var row = table.insertRow(rowCount);
		var colCount = table.rows[0].cells.length;
		for(var i=0; i<colCount; i++) {
			var newcell = row.insertCell(i);
			newcell.innerHTML = table.rows[0].cells[i].innerHTML;
		}
	}else{
		 alert("Maximum Passenger per ticket is 5.");
			   
	}
}

function deleteRow(tableID) {
	var table = document.getElementById(tableID);
	var rowCount = table.rows.length;
	for(var i=0; i<rowCount; i++) {
		var row = table.rows[i];
		var chkbox = row.cells[0].childNodes[0];
		if(null != chkbox && true == chkbox.checked) {
			if(rowCount <= 1) { 						// limit the user from removing all the fields
				alert("Cannot Remove all the Passenger.");
				break;
			}
			table.deleteRow(i);
			rowCount--;
			i--;
		}
	}
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
   <legend>Invoice Details</legend>
        <p> 
          <input type="button" value="Add Row" onClick="addRow('dataTable')" /> 
          <input type="button" value="Remove Row" onClick="deleteRow('dataTable')"  /> 
          <p>(All acions apply only to entries with check marked check boxes only.)</p>
        </p>
               <table id="dataTable" class="form" border="0">
                  <tbody>
                    <tr>
                      <p>
            <td><input type="checkbox" required="required" name="chk[]" checked="checked" /></td>
            <td>
              <label>Item Name</label>
              <input type="text" required="required" name="BX_NAME[]">
             </td>
             <td>
              <label for="BX_price">Price</label>
              <input type="text" required="required"   name="BX_price[]">
               </td>
             
              </p>
                    </tr>
                    </tbody>
                </table>

Answer 1

要将每一个都放入数据库，请尝试将 PHP mysql 命令放入 foreach 循环中，如下所示:

foreach($BX_NAME as $a => $b){
    echo $BX_NAME[$a]; 
    echo $BX_price[$a]; 

    $query = "INSERT INTO company_invoices(company_name,contact_name,BX_NAME,BX_price,added_by,date_added) VALUES('$company_name','$contact_name','$BX_NAME[$a]','$BX_price[$a]', ' $added_by',now())";
   $res = mysql_query($query);

}