根据规范,我必须使用 GridWorld 制作一个功能正常的 Tic Tac Toe 游戏。我已经完成了大部分类(class),但有一个方法我一直坚持不下去。我不知道如何检查对角线或垂直方向是否有赢家。下面是方法。
public String getWinner()
{
Grid<Piece> grid = getGrid();
if(grid == null)
{
return "no winner";
}
String winner = "";
for (int r = 0; r<grid.getNumRows(); r++)
{
Piece row0 = grid.get(new Location(r,0));
Piece row1 = grid.get(new Location(r,1));
Piece row2 = grid.get(new Location(r,2));
if(row0 == null || row1 == null || row2 == null)
{
continue;
}
if(row0.getName().equals(row1.getName()) && row0.getName().equals(row2.getName()))
{
winner = row0.getName()+ " wins horizontally!";
break;
}
}
//check for vertical winner
//check for diagonal winner
if(isWorldFull() && winner.length() == 0)
{
winner = "cat's game - no winner!\n\n";
}
else if(!isWorldFull() && winner.length() == 0)
{
winner = "no winner";
}
return winner;
}
任何和所有的帮助将不胜感激。
最佳答案
// vertically
for (int c = 0; r<grid.getNumCols(); c++)
{
Piece col0 = grid.get(new Location(0,c));
Piece col1 = grid.get(new Location(1,c));
Piece col2 = grid.get(new Location(2,c));
if(col0 == null || col1 == null || col2 == null)
{
continue;
}
if(col0.getName().equals(col1.getName()) && col0.getName().equals(col2.getName()))
{
winner = col0.getName()+ " wins vertically!";
break;
}
}
// diagonal 1
for (int x = 0; r<grid.getNumRows(); x++)
{
Piece d0 = grid.get(new Location(x,x));
Piece d1 = grid.get(new Location(x,x));
Piece d2 = grid.get(new Location(x,x));
if(d0 == null || d1 == null || d2 == null)
{
continue;
}
if(d0.getName().equals(d1.getName()) && d0.getName().equals(d2.getName()))
{
winner = d0.getName()+ " wins diagonally!";
break;
}
}
// diagonal 2
for (int x = 0; r<grid.getNumRows(); x++)
{
Piece d0 = grid.get(new Location(x,2-x));
Piece d1 = grid.get(new Location(x,2-x));
Piece d2 = grid.get(new Location(x,2-x));
if(d0 == null || d1 == null || d2 == null)
{
continue;
}
if(d0.getName().equals(d1.getName()) && d0.getName().equals(d2.getName()))
{
winner = d0.getName()+ " wins diagonally!";
break;
}
}
请注意,您可以将用于比较三个单元格 (row0,1,2,col0,1,2,d0,1,2) 的代码提取到一个单独的方法中,如下所示:
boolean check3Pieces(Piece p0, Piece p1, Piece p2, String caption) {
if(p0 == null || p1 == null || p2 == null)
{
return false;
}
if(p0.getName().equals(p1.getName()) && p0.getName().equals(p2.getName()))
{
winner = p0.getName()+ " " + caption;
return true;
}
return false;
}
关于Java Tic Tac Toe 错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21592109/