我已经创建了一个主页,用户可以从该主页登录该应用程序,然后在下一个屏幕中用户可以看到他们的个人资料信息(仅个人资料名称),并在其下方是他们的退出按钮。用户可以使用注销按钮从应用程序中注销。但这对我不起作用。
我想通过按 details.dart 中的 signOut 按钮从 main.dart 调用 signOut 方法(两个类都在不同的文件中)
但是当我在 details.dart 中按下 signOut 按钮时没有任何反应!
代码如下:
main.dart
import 'dart:async';
import 'package:flutter/material.dart';
import 'package:firebase_auth/firebase_auth.dart';
import 'package:google_sign_in/google_sign_in.dart';
import 'details.dart';
void main() => runApp(new MyApp());
class MyApp extends StatelessWidget {
@override
Widget build(BuildContext context) {
return new MaterialApp(
theme: new ThemeData(
primarySwatch: Colors.blue,
),
debugShowCheckedModeBanner: false,
home: new MyHomePage(),
);
}
}
class MyHomePage extends StatefulWidget {
@override
MyHomePageState createState() => MyHomePageState();
}
class MyHomePageState extends State<MyHomePage> {
final FirebaseAuth firebaseAuth = FirebaseAuth.instance;
final GoogleSignIn googleSignIn = GoogleSignIn();
static bool _LoginButton = true;
void signOut(){
googleSignIn.signOut();
setState((){
_LoginButton = true;
});
print(_LoginButton);
print("User Signed Out");
}
Future<FirebaseUser> _signIn() async{
if(_LoginButton==true){
setState((){
_LoginButton=false;
});
GoogleSignInAccount googleSignInAccount = await googleSignIn.signIn();
GoogleSignInAuthentication googleSignInAuthentication = await googleSignInAccount.authentication;
FirebaseUser firebaseUser = await firebaseAuth.signInWithGoogle(idToken: googleSignInAuthentication.idToken, accessToken: googleSignInAuthentication.accessToken);
print("Username is "+firebaseUser.displayName);
setState((){
_LoginButton = true;
});
Navigator.push(context, MaterialPageRoute(builder: (context) => details(firebaseUser.displayName,signOut)));
return firebaseUser;
}
}
bool _LoginButtonBool(){
return _LoginButton;
}
@override
Widget build(BuildContext context) {
return Scaffold(
appBar: AppBar(title: Text("Google auth with firebase"),),
body: Center(
child: _LoginButtonBool()?Container(
child: Column(
mainAxisAlignment: MainAxisAlignment.spaceAround,
children: <Widget>[
MaterialButton(onPressed: _LoginButtonBool() ? () => _signIn().then((FirebaseUser firebaseuser ) =>print(firebaseuser)).catchError((e) => print(e)): null,
child: Text("Login"),color: Colors.orange,),
],
),
):CircularProgressIndicator(backgroundColor: Colors.greenAccent.withOpacity(0.01),),
),
);
}
}
details.dart
import 'package:flutter/material.dart';
import 'package:flutter_auth/main.dart';
class details extends StatelessWidget {
String name;
final Function callback;
details(this.name,this.callback);
@override
Widget build(BuildContext context) {
return Scaffold(
body:Center(child: Column(
mainAxisAlignment: MainAxisAlignment.spaceAround,
children: <Widget>[
Text(name),
MaterialButton(onPressed: () => callback,
child: Text("Log out"),color: Colors.orange),
],
),),
);
}
}
最佳答案
很简单,我举个例子来解释
class Animals
{
var animalList = ['dog','cat','cow'];
// function for printing the list of animals
void animalListPrinter(){
for(var animal in animalList){
print(animal);
}
}
}
将上述函数调用到另一个类
class ShowingAnimalList extends StatelessWidget {
final Animals ani= new Animals();
@override
Widget build(BuildContext context) {
return GestureDetector(
onTap:()=> ani.animalListPrinter(),
);
}
}
You can call any Widget with this from the parent class
关于dart - 如何从 Flutter(Dart) 中的另一个类调用方法?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52549440/