我正在创建一个与 SOAP Web 服务交互以从数据库获取数据的应用程序。 当用户通过 web-services 传递用户名和密码成功登录时，会为该用户提供一个唯一的 session ID。稍后在其他 Activity 中调用 Web 服务方法时将需要此 session ID。我的问题是，如何在需要时将该 session ID 传递给下一个 Activity 并维护它直到用户注销。 例如: 这是一个Web服务方法，需要传递SID( session ID)，我如何获取登录时给我的 session ID，并将其用于此方法
-<element name="createAttachment">
-<complexType>
-<sequence>
<element name="sid" type="xsd:int"/>
<element name="repositoryHandle" type="xsd:string"/>
<element name="objectHandle" type="xsd:string"/>
<element name="description" type="xsd:string"/>
<element name="fileName" type="xsd:string"/>
</sequence>
</complexType>
</element>
那是我的login.java。我可以成功登录并获得 session ID
public class Login extends ActionBarActivity implements OnClickListener {
private static final String NAMESPACE = "***";
private static final String URL = ***";
private static final String METHOD_NAME = "login";
private static final String SOAP_ACTION = NAMESPACE + "/" + METHOD_NAME; //in wsdl it's nothing
EditText usersusername, userspassword;
Button LB;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_login);
LB = (Button) findViewById(R.id.loginbutton);
LB.setOnClickListener(this);
usersusername = (EditText)findViewById(R.id.editusername);
userspassword = (EditText)findViewById(R.id.editpassword);
}
public void onClick(View view){
switch (view.getId()){
case R.id.loginbutton:
new LongOperation().execute("");
break;
}
}
private class LongOperation extends AsyncTask<String, Void, String>{
@Override
protected String doInBackground(String... params) {
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
usersusername = (EditText)findViewById(R.id.editusername);
userspassword = (EditText)findViewById(R.id.editpassword);
String user_Name = usersusername.getText().toString();
String user_Password = userspassword.getText().toString();
PropertyInfo unameProp =new PropertyInfo();
unameProp.setName("userName");//Define the variable name in the web service method
unameProp.setValue(user_Name);//set value for userName variable
unameProp.setType(String.class);//Define the type of the variable
request.addProperty("username",user_Name);//Pass properties to the variable
PropertyInfo passwordProp =new PropertyInfo();
passwordProp.setName("password");
passwordProp.setValue(user_Password);
passwordProp.setType(String.class);
request.addProperty(passwordProp);
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); // Declare the version of the soap request
envelope.setOutputSoapObject(request);
try {
HttpTransportSE aht = new HttpTransportSE(URL);
aht.call(SOAP_ACTION, envelope); //this is the actual part that calls the web service
SoapPrimitive result =(SoapPrimitive)envelope.getResponse();
String Something = result.toString(); // Result string
System.out.println(Something);
if (!TextUtils.isEmpty(Something))
{
Intent intent = new Intent(Login.this,Dashboard.class);
intent.putExtra("username",usersusername.getText().toString());
startActivity(intent);
}
}
catch (Exception e){
e.printStackTrace();
}
return null;
} // closing bracket of do in background
@Override
// show dialog and prepare the fields for retry
}
}
} // closing bracket of long operation
}
最佳答案
您可以将 sessionID 保存在共享首选项中，并在注销时从共享首选项中删除 sessionID。 请参阅此链接 Example
关于java - Android 中用于 Web 服务的 ID session 管理，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/24666904/