嗨,我正在尝试将默认主页更改为另一个页面,但我无法做到这一点,因此我尝试将页面从默认主页重定向到我想要的页面,但出现此错误 未找到带有 URI 的 HTTP 请求的映射:
[/myapp/WEB-INF/views/index.html] in DispatcherServlet with name 'appServlet'
这是我的设置,当我使用 spring 工具套件创建项目时,我默认保留了所有内容
这是我的 servlet-contex.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
<!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure -->
<!-- Enables the Spring MVC @Controller programming model -->
<annotation-driven />
<!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory -->
<resources mapping="/resources/**" location="/resources/" />
<!-- Resolves views selected for rendering by @Controllers to .jsp resources in the /WEB-INF/views directory -->
<beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<beans:property name="prefix" value="/WEB-INF/views/" />
<beans:property name="suffix" value="" />
</beans:bean>
<context:component-scan base-package="com.proj.myapp" />
这是我的 web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<!-- The definition of the Root Spring Container shared by all Servlets and Filters -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/root-context.xml</param-value>
</context-param>
<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<!-- Processes application requests -->
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
这是我的默认主文件
home.jsp
enter code here
<%@ taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c" %>
<%@ page session="false" %>
<html>
<head>
<title>Home</title>
</head>
<body>
<h1>
Hello world!
<c:redirect url="/indice.html"/>
</h1>
</body>
</html>
这是我想要重定向的页面
enter code here
<html>
<body>
<h1>
INDICE
</h1>
</body>
</html>
和我的 Controller
@Controller
public class HomeController {
@RequestMapping(value = "/")
public String home() {
return "home.jsp";
}
@RequestMapping(value = "/indice.html")
public String indice() {
return "indice.html";
}
}
我收到这个错误
No mapping found for HTTP request with URI: [/myapp/WEB-INF/views/indice.html] in DispatcherServlet with name 'appServlet'
最佳答案
由于您的代码后缀属性值为空,因此您需要将后缀类型传递给 servlet-context.xml 中的此属性。
你必须改变它
<beans:property name="suffix" value=".jsp" />
然后你的indices.html到indices.jsp然后它就可以工作了。
但是,如果您想使用 html 文件来处理它,但 .html 文件是静态的并且不需要 servlet 处理,那么使用映射会更有效、更简单。这需要 Spring 3.0.4+。
例如:
<mvc:resources mapping="/static/**" location="/static/" />
它将传递所有以/static/开头的请求到 webapp/static/目录。
因此,将indices.html放入webapp/static/并使用return“indices.html”;根据你的方法,Spring 应该找到 View 。
关于java - spring 工具套件默认 mvc 项目 Web 应用程序,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25509483/