我有一个 JSON,我想将它放入可打包类中,以便我可以将其对象从一个 Activity 传递到另一个 Activity 。我之前已经使用过 Parcelable 好几次了。但这一次我对如何使用下面的 JSON 响应创建 Parcelable 类感到困惑。
实际上困惑在于 List<String[]>
String[]
的数组列表我怎样才能通过这个。
[
{
puzzle_title: "Puzzle",
grid_size: "8",
data: [
[
"J",
"J",
"P",
"Y",
"B",
"T",
"P",
"U"
],
[
"L",
"W",
"B",
"I",
"Q",
"M",
"S",
"L"
],
[
"K",
"Y",
"Q",
"L",
"N",
"A",
"W",
"D"
],
[
"Y",
"E",
"I",
"G",
"U",
"G",
"H",
"V"
],
[
"B",
"L",
"A",
"C",
"K",
"E",
"I",
"F"
],
[
"X",
"L",
"Q",
"T",
"B",
"N",
"T",
"B"
],
[
"O",
"O",
"R",
"E",
"D",
"T",
"E",
"W"
],
[
"H",
"W",
"B",
"K",
"H",
"A",
"F",
"V"
]
],
words: [
"RED",
"YELLOW",
"BLUE",
"BLACK",
"WHITE",
"MAGENTA"
]
},
{}
]
我已经编写了如下所示的可打包类..
public class PuzzelSetter implements Parcelable {
@SerializedName("puzzle_title")
private String title;
@SerializedName("grid_size")
private int size;
private List<String[]> data = new ArrayList<String[]>();
private List<String> words = new ArrayList<String>();
public String getTitle() {
return title;
}
public List<String[]> getData() {
return data;
}
public void setData(List<String[]> data) {
this.data = data;
}
public List<String> getWords() {
return words;
}
public void setWords(List<String> words) {
this.words = words;
}
public void setTitle(String title) {
this.title = title;
}
public int getSize() {
return size;
}
public void setSize(int size) {
this.size = size;
}
public void setData(ArrayList<String[]> data) {
this.data = data;
}
public void setWords(ArrayList<String> words) {
this.words = words;
}
@Override
public int describeContents() {
return 0;
}
@Override
public void writeToParcel(Parcel dest, int flags) {
dest.writeString(title);
dest.writeInt(size);
dest.writeList(data);
dest.writeStringList(words);
}
public static final Parcelable.Creator<PuzzelSetter> CREATOR = new Parcelable.Creator<PuzzelSetter>() {
@Override
public PuzzelSetter createFromParcel(Parcel source) {
return new PuzzelSetter(source);
}
@Override
public PuzzelSetter[] newArray(int size) {
return new PuzzelSetter[size];
}
};
public PuzzelSetter(Parcel parcel) {
title = parcel.readString();
size = parcel.readInt();
//data = parcel.readStringArray(val);
parcel.readStringList(words);
}
}
更新:
@Override
public void writeToParcel(Parcel dest, int flags) {
dest.writeString(title);
dest.writeInt(size);
dest.writeStringList(words);
dest.writeInt(data.size()); // write list size
for (String[] letters : data) {
dest.writeStringArray(letters); //write each element
}
}
public PuzzelSetter(Parcel parcel) {
title = parcel.readString();
size = parcel.readInt();
//List<String[]> data = new ArrayList<String[]>();
int size = parcel.readInt(); // read size
for (int i = 0; i < size; i++) {
String[] letters = parcel.createStringArray(); // read each element
data.add(letters);
}
parcel.readStringList(words);
}
欢迎任何建议。
提前致谢。
最佳答案
您可以将所有列表元素分别写入parcel:
dest.writeInt(data.size()); // write list size
for (String[] letters : data) {
dest.writeStringArray(letters); //write each element
}
以及如何阅读它:
List<String[]> data = new ArrayList<String[]>();
int size = parcel.readInt(); // read size
for (int i = 0; i < size; i++) {
String[] letters = parcel.createStringArray(); // read each element
data.add(letters);
}
更新:
就您而言:
@Override
public void writeToParcel(Parcel dest, int flags) {
dest.writeString(title);
dest.writeInt(size);
dest.writeStringList(words);
dest.writeInt(data.size()); // write list size
for (String[] letters : data) {
dest.writeStringArray(letters); //write each element
}
}
public PuzzelSetter(Parcel parcel) {
title = parcel.readString();
size = parcel.readInt();
parcel.readStringList(words);
int size = parcel.readInt(); // read size
for (int i = 0; i < size; i++) {
String[] letters = parcel.createStringArray(); // read each element
data.add(letters);
}
}
关于java - Android 可打包列表<String[]>,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25601517/