我制作了一个数据库电影应用程序,它允许用户搜索电影。结果将显示在 ScrollView 中。返回搜索结果后,我希望用户能够单击电影,这将导致一个包含电影完整详细信息的新 Activity 。我该如何去做呢?
所有点击都将导致一项 Activity ,但我需要根据点击的影片显示不同的详细信息。我的数据库中总共有 20 部电影。
MainActivity 上的搜索功能:
public void search(View v){
EditText search = (EditText)findViewById(R.id.edtSearch);
String searchresult = "%" + search.getText().toString() + "%";
db = new DbHelper(this).getReadableDatabase();
String[] tblColumns = {"*"};
String where = "film LIKE ? OR actor LIKE ? OR actor2 LIKE ? OR director LIKE ?";
String[] args = {searchresult, searchresult, searchresult, searchresult};
Cursor results = db.query("FILMTABLE", tblColumns, where, args, null, null, null);
film(results);
}
public void film (Cursor c){
c.moveToFirst();
int titleint = c.getColumnIndex("film");
int id= c.getColumnIndex("id");
String title = c.getString(titleint);
int filmID = c.getInt(id);
TextView txt = new TextView(getApplicationContext());
txt.setId(filmID);
txt.setText(title);
txt.setTextColor(Color.BLACK);
txt.setTextSize(15);
txt.setClickable(true);
txt.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
Intent intent = new Intent(getApplicationContext(), MainActivity4.class);
startActivity(intent);
}
});
ScrollView scrollView = (ScrollView)findViewById(R.id.scrolLView);
scrollView.addView(txt);
}
数据库助手:
import android.content.ContentValues;
import android.content.Context;
import android.database.Cursor;
import android.database.sqlite.SQLiteDatabase;
import android.database.sqlite.SQLiteOpenHelper;
public class DbHelper extends SQLiteOpenHelper {
private static final String ID = "id";
private static final String FILM = "film";
private static final String ACTOR = "actor";
private static final String ACTOR2 = "actor2";
private static final String DIRECTOR = "director";
private static final String DESCRIPTION = "description";
private static final String TABLE_NAME = "FILMTABLE";
private static final String DATABASE_NAME = "filmdatabase3";
private static final int DATABASE_VERSION = 1;
private static final boolean FAVOURITE = false;
public DbHelper(Context context) {
super(context, DATABASE_NAME, null, DATABASE_VERSION);
}
@Override
public void onCreate(SQLiteDatabase db) {
db.execSQL("CREATE TABLE " + TABLE_NAME + " (" +
ID + " INTEGER PRIMARY KEY AUTOINCREMENT, " +
FILM + " TEXT NOT NULL, " +
ACTOR + " TEXT NOT NULL, " +
ACTOR2 + " TEXT NOT NULL, " +
DIRECTOR + " TEXT NOT NULL, " +
FAVOURITE + " BOOLEAN, " +
DESCRIPTION + " TEXT NOT NULL);"
);
Cursor countRows = db.rawQuery("SELECT count(*) FROM FILMTABLE", null);
countRows.moveToFirst();
int NumRows = countRows.getInt(0);
countRows.close();
if (NumRows == 0) {
ContentValues values = new ContentValues();
values.put("film", "Gone Girl");
values.put("actor", "Ben Affleck");
values.put("actor2", "Rosamund Pike");
values.put("director", "David Fincher");
values.put("description", "description");
db.insert("FILMTABLE", null, values);
values.clear();
values.put("film", "The Hobbit");
values.put("actor", "Martin Freeman");
values.put("actor2", "Elijah Wood");
values.put("director", "Peter Jackson");
values.put("description", "description");
db.insert("FILMTABLE", null, values);
values.clear();
}
}
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
db.execSQL("DROP TABLE IF EXISTS" + TABLE_NAME);
onCreate(db);
}
}
最佳答案
当您开始详细 Activity 时,将影片的 id 放入您正在创建的 Intent 中。
Intent intent = new Intent(getApplicationContext(), MainActivity4.class);
intent.putExtra("FILM_ID_KEY", getSelectedFilmId());
startActivity(intent);
或者制作您的电影 POJO parcelable并再次通过 putExtra 将其放入您的 Intent 中方法。
之后,在 MainActivity4 中使用 getIntent 在 onCreate 中获取这些值方法。
关于java - 如何根据用户点击检索数据库值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28897441/