我是 Spring 新手,我正在尝试学习开发一个简单的应用程序。
这是数据库的架构: /image/3H4jd.png
非常简单,每个用户都必须首先登录,一旦登录,就会显示管理员所在的团队列表。该信息存储在表team_members
中INSERT INTO team_members (user_id, team_id, role) VALUES ('1', '1', 'admin');
INSERT INTO team_members (user_id, team_id, role) VALUES ('1', '2', 'admin');
INSERT INTO team_members (user_id, team_id, role) VALUES ('2', '2', 'player');
INSERT INTO team_members (user_id, team_id, role) VALUES ('2', '3', 'admin');
当用户尝试编辑或访问要编辑其中一个团队的页面时,就会出现问题。这是我的 Controller 来执行此操作:
@RequestMapping(value="teams/{id}/edit", method=RequestMethod.GET)
public ModelAndView editTeamPage(@PathVariable Integer id) {
ModelAndView modelAndView = new ModelAndView("edit-team-form");
Team team = teamService.getTeam(id);
modelAndView.addObject("team",team);
return modelAndView;
}
为了能够访问此页面,该用户必须经过身份验证 isAuthenticated()
,但是,我还想检查表 team_members 中用户的角色是否为admin。
所以我的问题是,最好的方法是什么?我是否应该在必须验证此条件的每个 Controller 函数的开头插入一个 if ?有没有更清洁的解决方案?
我尝试创建
package com.sports.beans;
import org.springframework.stereotype.Component;
@Component("mySecurityService")
public class MySecurityService {
public boolean hasPermission(String key) {
return false;
}
}
并向 Controller 函数添加了 @PreAuthorize("@mySecurityService.hasPermission('special')")
但它不起作用。编辑:未调用方法 mySecurityService.hasPermission(...)
这是我的spring-security.xml
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.2.xsd">
<global-method-security pre-post-annotations="enabled" />
<!-- enable use-expressions -->
<http auto-config="true" use-expressions="true">
<intercept-url pattern="/admin**" access="hasRole('ROLE_ADMIN')" />
<intercept-url pattern="/user**" access="hasRole('ROLE_USER')" />
<intercept-url pattern="/teams/**" access="isAuthenticated()" />
<!-- access denied page -->
<access-denied-handler error-page="/403" />
<form-login login-page="/login" authentication-failure-url="/login?error"
username-parameter="username" password-parameter="password" />
<logout logout-success-url="/login?logout" />
<!-- enable csrf protection -->
<csrf />
</http>
<authentication-manager>
<authentication-provider user-service-ref="myUserDetailsService">
<password-encoder hash="bcrypt"/>
</authentication-provider>
</authentication-manager>
<beans:bean id="mySecurityService" class="com.sports.beans.MySecurityService" />
</beans:beans>
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
version="3.0">
<display-name>Sports</display-name>
<!-- Spring MVC -->
<servlet>
<servlet-name>mvc-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>mvc-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/spring-database.xml,
/WEB-INF/spring-security.xml
</param-value>
</context-param>
<!-- Spring Security -->
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<filter>
<filter-name>hibernateFilter</filter-name>
<filter-class>org.springframework.orm.hibernate4.support.OpenSessionInViewFilter</filter-class>
<init-param>
<param-name>singleSession</param-name>
<param-value>true</param-value>
</init-param>
</filter>
<filter-mapping>
<filter-name>hibernateFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
</web-app>
spring-database.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:sec="http://www.springframework.org/schema/security"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-4.0.xsd
http://www.springframework.org/schema/aop
http://www.springframework.org/schema/aop/spring-aop-4.0.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-4.0.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.2.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd">
<bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close">
<property name="driverClassName" value="com.mysql.jdbc.Driver"/>
<property name="url" value="jdbc:mysql://localhost:3306/test_sports"/>
<property name="username" value="root"/>
<property name="password" value="lol123" />
</bean>
<bean id="sessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<property name="dataSource" ref="dataSource"/>
<property name="annotatedClasses">
<list>
<value>com.sports.models.User</value>
<value>com.sports.models.UserRole</value>
<value>com.sports.models.Team</value>
<value>com.sports.models.TeamMember</value>
</list>
</property>
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.MySQL5Dialect</prop>
<prop key="hibernate.format_sql">true</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
</bean>
<bean id="userDao" class="com.sports.dao.UserDaoImpl">
<property name="sessionFactory" ref="sessionFactory"/>
</bean>
<context:component-scan base-package="com.sports" />
<bean id="myUserDetailsService" class="com.sports.service.MyUserDetailsService">
<property name="userDao" ref="userDao"/>
</bean>
<bean id="transactionManager" class="org.springframework.orm.hibernate4.HibernateTransactionManager">
<property name="sessionFactory" ref="sessionFactory"/>
</bean>
<tx:advice id="txAdvice" transaction-manager="transactionManager">
<tx:attributes>
<tx:method name="get*" read-only="true"/>
<tx:method name="find*" read-only="true"/>
<tx:method name="*"/>
</tx:attributes>
</tx:advice>
<aop:config>
<aop:pointcut id="userServicePointCut" expression="execution(* com.sports.service.*Service.*(..))"/>
<aop:advisor advice-ref="txAdvice" pointcut-ref="userServicePointCut"/>
</aop:config>
</beans>
mvc-dispatcher-servlet.xml
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<context:component-scan base-package="com.sports.*"/>
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/pages/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
</beans>
最佳答案
为了让 @PreAuthorize
影响代码,您需要确保 enable method security 。例如:
<global-method-security pre-post-annotations="enabled" />
一个常见的问题是用户将在其 Controller 上定义安全注释以及父上下文中的 global-method-security 元素。这是行不通的。
global-method-security 元素必须在与您尝试保护的资源相同的 Spring 上下文中定义。例如,如果根 ApplicationContext 定义了您要保护的服务 bean,那么它还应该引用包含 global-method-security 的配置。
对于您的示例,这可能意味着所有配置都应由 web.xml 中的以下内容选取:
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/spring-database.xml,
/WEB-INF/spring-security.xml
</param-value>
</context-param>
关于java - Spring框架, Controller PreAuthorize中自定义函数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29330135/