我正在尝试从 eclipse 运行 Hibernate 配置并从中创建数据库结构。在运行配置时,我收到以下异常:
java.sql.SQLException: ORA-00942: table or view does not exist
java.sql.SQLException: ORA-00904: : invalid identifier errors.
我使用注释来创建 hbm/pojo。 下面是代码。我不确定我是否遗漏了一些东西。有什么帮助吗?
配置: eclipse 开普勒 SR2 hibernate 核心 4+ 甲骨文10g 适用于 Eclipse 的 JDK 8
import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.JoinTable;
import javax.persistence.ManyToMany;
import javax.persistence.JoinColumn;
import javax.persistence.OneToMany;
import javax.persistence.Table;
@Entity
public class RuleQuestion {
//ATTRIBUTES
@Id
@GeneratedValue(strategy =GenerationType.AUTO)
private Long id;
//QUestion NAME On JSP
private String jspQuestion;
//LEVEL of Question in RULE DATA MODEL
private int level;
//IF QUESTION has CHILD questions associated with it
private boolean hasChildren;
//IS MULTISELECT
private boolean isMultiselect;
//POSSIBLE ANSWERS FOR QUESTION
/*@OneToMany(cascade = CascadeType.ALL, mappedBy = "question")
private List<RuleAnswer> possibleAnswers =new ArrayList<RuleAnswer>(0);
*///ANSWER for Question
private String answer;
//DEFEAULT ANSWER
private String defaultAnswer;
/*//ASSOCIATED CHILDREN QUESTIONS
private List<RuleQuestion> associatedQuestions;*/
//Visibility
private String visibility;
public RuleQuestion()
{
}
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getJspQuestion() {
return jspQuestion;
}
public void setJspQuestion(String jspQuestion) {
this.jspQuestion = jspQuestion;
}
public int getLevel() {
return level;
}
public void setLevel(int level) {
this.level = level;
}
public boolean isHasChildren() {
return hasChildren;
}
public void setHasChildren(boolean hasChildren) {
this.hasChildren = hasChildren;
}
public boolean isMultiselect() {
return isMultiselect;
}
public void setMultiselect(boolean isMultiselect) {
this.isMultiselect = isMultiselect;
}
public String getAnswer() {
return answer;
}
public void setAnswer(String answer) {
this.answer = answer;
}
public String getDefaultAnswer() {
return defaultAnswer;
}
public void setDefaultAnswer(String defaultAnswer) {
this.defaultAnswer = defaultAnswer;
}
public String getVisibility() {
return visibility;
}
public void setVisibility(String visibility) {
this.visibility = visibility;
}
}
最佳答案
在 @Entity 之后添加以下行。
@Table(name="RuleQuestion")
@Table 注释允许您指定将用于将实体保存在数据库中的表的详细信息。
@Table 注释提供了四个属性,允许您覆盖表的名称、目录和架构,并对表中的列强制执行唯一约束。现在我们只使用表名 EMPLOYEE。
同时添加
@Id
@GeneratedValue
@Column(name = "ID")
private Integer id;
我有生成表的类
@Entity
@Table(name = "TRANSACTION")
public class Transaction {
@Id
@GeneratedValue
@Column(name = "ID")
private Integer id;
@Column(name="OCPP_START_TAG_ID",nullable=false)
private String ocppStartTagId;
}
关于java - hibernate 映射 - 运行 hibernate 配置时出现错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30119824/