我有一个联系人应用程序，它使用 ArrayAdapter 显示联系人的所有姓名。这工作正常，但我想每当我单击姓名时打开 native 联系人应用程序，其中包含联系人的详细信息。
提前谢谢您!
public class MainActivity extends ListActivity {
private CustomAdapter customAdapter;
List<String> contacts = new ArrayList<String>();
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
ListView lv = (ListView) findViewById(android.R.id.list);
customAdapter = new CustomAdapter(this);
lv.setAdapter(customAdapter);
}
@Override
protected void onResume() {
super.onResume();
Log.d("TAG","onresume");
loadApps();
}
public void loadApps(){
//Cursor cursor = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, null, null, null);
Cursor cursor;
ContentResolver contentResolver = getContentResolver();
cursor = contentResolver.query(ContactsContract.Contacts.CONTENT_URI,null,
ContactsContract.Contacts.HAS_PHONE_NUMBER + " = 1",
null,
"UPPER(" + ContactsContract.Contacts.DISPLAY_NAME + ") ASC");
customAdapter.clear();
if (cursor.getCount() > 0) {
cursor.moveToFirst();
do {
String name = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
contacts.add(name);
} while (cursor.moveToNext());
}
cursor.close();
for (String names : contacts) {
AppInfoItem appInfoItem = new AppInfoItem();
appInfoItem.name = names;
customAdapter.add(appInfoItem);
}
}
@Override
protected void onListItemClick(ListView l, View v, int position, long id) {
super.onListItemClick(l, v, position, id);
Intent intent = new Intent(Intent.ACTION_VIEW,
Uri.parse("content://contacts/people/"));
if (intent != null) {
startActivity(intent);
}
}
}
CustomArrayAdapter.class
public class CustomAdapter extends ArrayAdapter<String> {
LayoutInflater layoutInflater;
public CustomAdapter(Context context) {
super(context, 0);
layoutInflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
// Create cell and populate with data of the array
if (convertView == null)
convertView = layoutInflater.inflate(android.R.layout.simple_list_item_1, parent, false);
AppInfoItem item = (AppInfoItem) getItem(position);
//String name = names[position];
TextView textView = (TextView) convertView.findViewById(android.R.id.text1);
textView.setText(item.name);
return convertView;
}
}
AppInfoItem.class
public class AppInfoItem {
String name;
String id;
}
最佳答案
我认为您需要将 Intent 与 ACTION_VIEW action 一起使用并将 Intent 数据设置为表单的联系人 URI
content://contacts/people/1
如第一个示例所示http://developer.android.com/reference/android/content/Intent.html#IntentStructure
关于java - 如何在 Android 中使用 onListItemClick 在 listView 中打开带有联系人姓名的联系人详细信息卡？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/30189098/