有人能明白为什么用户可以输入超过 27 个苹果、蓝莓或花生馅饼吗？即使在为每种类型的饼图的最大数量声明了最终 int 后也是如此。
这里的目的是不断提示用户输入饼图类型，直到用户想要退出。每次输入有效输入之一时，它都会存储在自己的数组中。用户指示完成后，计算完成并打印一条消息。
import javax.swing.JOptionPane;
public class CalcPieProfit {
public static void main(String[] args) {
final int MAX_PER_TYPE = 27;
int appleTotal = 0;
int blueberryTotal = 0;
int peanutTotal = 0;
String typeOfPie = getPieType();
while (!typeOfPie.equalsIgnoreCase("q")) {
if (typeOfPie.equalsIgnoreCase("apple")) {
String[] appleArray = fillApple(typeOfPie, MAX_PER_TYPE);
appleTotal++;
}
else if (typeOfPie.equalsIgnoreCase("blueberry")) {
String[] blueberryArray = fillBlueberry(typeOfPie, MAX_PER_TYPE);
blueberryTotal++;
}
else if (typeOfPie.equalsIgnoreCase("peanut")) {
String[] peanutArray = fillPeanut(typeOfPie, MAX_PER_TYPE);
peanutTotal++;
}
typeOfPie = getPieType();
}
if (typeOfPie.equalsIgnoreCase("q")) {
int totalPies = calcTotalPies(appleTotal, blueberryTotal, peanutTotal);
double profit = calcProfit(appleTotal, blueberryTotal, peanutTotal);
printReport(totalPies, appleTotal, blueberryTotal, peanutTotal, profit);
}
}
public static String getPieType() {
String pieType;
do {
try {
pieType = JOptionPane.showInputDialog("Enter a pie type:");
}
catch (NumberFormatException e) {
pieType = "";
}
if (!pieType.equalsIgnoreCase("apple") && !pieType.equalsIgnoreCase("blueberry") &&
!pieType.equalsIgnoreCase("peanut") && !pieType.equalsIgnoreCase("q")) {
JOptionPane.showMessageDialog(null, "Enter 'apple', 'blueberry', 'peanut', or 'q' only.");
}
} while (!pieType.equalsIgnoreCase("apple") && !pieType.equalsIgnoreCase("blueberry") &&
!pieType.equalsIgnoreCase("peanut") && !pieType.equalsIgnoreCase("q"));
return pieType;
}
public static String[] fillApple(String typeOfPie, int MAX_PER_TYPE) {
String[] appleArray = new String[MAX_PER_TYPE];
for (int i = 0; i < appleArray.length; i++) {
appleArray[i] = typeOfPie;
}
return appleArray;
}
public static String[] fillBlueberry(String typeOfPie, int MAX_PER_TYPE) {
String[] blueberryArray = new String[MAX_PER_TYPE];
for (int i = 0; i < blueberryArray.length; i++) {
blueberryArray[i] = typeOfPie;
}
return blueberryArray;
}
public static String[] fillPeanut(String typeOfPie, int MAX_PER_TYPE) {
String[] peanutArray = new String[MAX_PER_TYPE];
for (int i = 0; i < peanutArray.length; i++) {
peanutArray[i] = typeOfPie;
}
return peanutArray;
}
public static int calcTotalPies(int appleTotal, int blueberryTotal, int peanutTotal) {
int total = appleTotal + blueberryTotal + peanutTotal;
return total;
}
public static double calcProfit (int appleTotal, int blueberryTotal, int peanutTotal) {
final double APPLE_PROFIT = 5.94;
final double BLUEBERRY_PROFIT = 5.89;
final double PEANUT_PROFIT = 6.95;
double profit = (APPLE_PROFIT * appleTotal) + (BLUEBERRY_PROFIT * blueberryTotal) +
(PEANUT_PROFIT * peanutTotal);
return profit;
}
public static void printReport(int totalPies, int appleTotal, int blueberryTotal, int peanutTotal, double profit) {
if (totalPies > 0) {
JOptionPane.showMessageDialog(null,
"Pie Report\n\n" +
"Total pies: " + totalPies +
"\nTotal of apple pie: " + appleTotal +
"\nTotal of blueberry pie: " + blueberryTotal +
"\nTotal of peanut butter pie: " + peanutTotal +
"\nTotal profit: $" + String.format("%.2f", profit));
}
else {
JOptionPane.showMessageDialog(null, "Enjoy your day off.");
}
}
}
最佳答案
您并没有真正使用String[]的appleArray、blueberryArray和peanutArray - 它们是在各自的方法中创建的，但不在其他地方使用。为了计算利润，您(理所当然)只是总变量。
而不是
if (typeOfPie.equalsIgnoreCase("apple")) {
String[] appleArray = fillApple(typeOfPie, MAX_PER_TYPE);
appleTotal++;
}
你应该做类似的事情
if (typeOfPie.equalsIgnoreCase("apple")) {
if (appleTotal >= MAX_PER_TYPE) {
JOptionPane.showMessageDialog(null, "Too many apples.");
} else {
appleTotal++;
}
}
(对于其他饼图类型也是如此)。
关于java - 超过数组长度后仍存储用户输入，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/31358254/