我需要使用我无法修改的作业类来实现“循环”调度程序。循环调度程序应首先处理等待时间最长的作业,然后将计时器重置为零。如果两个作业的等待时间相同,则先处理 ID 较低的作业。作业类只提供三个值(作业 ID、剩余持续时间和优先级(这不是必需的)。每个作业都有一个开始时间,因此在第一个周期中可能只有几个作业可用,下一个周期可能会更多,等等。由于我每次调用它时调用的“作业数组”都是不同的,所以我不确定如何存储等待时间。
这是工作类别:
public class Jobs{
private int[] stas = new int[0];
private int[] durs = new int[0];
private int[] lefs = new int[0];
private int[] pris = new int[0];
private int[] fins = new int[0];
private int clock;
public Jobs()
{
this("joblist.csv");
}
public Jobs(String filename)
{
BufferedReader fp = null;
String line = "";
String[] b = null;
int[] tmp;
try
{
fp = new BufferedReader(new FileReader(filename));
while((line = fp.readLine()) != null)
{
b = line.split(",");
if(b.length == 3)
{
try
{
int sta = Integer.parseInt(b[0]);
//System.out.println("sta: " + b[0]);
int dur = Integer.parseInt(b[1]);
//System.out.println("dur: " + b[1]);
int pri = Integer.parseInt(b[2]);
//System.out.println("pri: " + b[2]);
stas = app(stas, sta);
//System.out.println("stas: " + Arrays.toString(stas));
durs = app(durs, dur);
//System.out.println("durs: " + Arrays.toString(durs));
lefs = app(lefs, dur);
//System.out.println("lefs: " + Arrays.toString(lefs));
pris = app(pris, pri);
//System.out.println("pris: " + Arrays.toString(pris));
fins = app(fins, -1);
//System.out.println("fins: " + Arrays.toString(fins));
}
catch(NumberFormatException e) {}
}
}
fp.close();
}
catch(FileNotFoundException e) { e.printStackTrace(); }
catch(IOException e) { e.printStackTrace(); }
clock = 0;
}
public boolean done()
{
boolean done = true;
for(int i=0; done && i<lefs.length; i++)
if(lefs[i]>0) done=false;
return done;
}
public int getClock() { return clock; }
public int[][] getJobs()
{
int count = 0;
for(int i=0; i<stas.length; i++)
if(stas[i]<=clock && lefs[i]>0)
count++;
int[][] jobs = new int[count][3];
count = 0;
for(int i=0; i<stas.length; i++)
if(stas[i]<=clock && lefs[i]>0)
{
jobs[count] = new int[]{i, lefs[i], pris[i]};
count++;
}
return jobs;
}
public int cycle() { return cycle(-1); }
public int cycle(int j)
{
if(j>=0 && j<lefs.length && clock>=stas[j] && lefs[j]>0)
{
lefs[j]--;
if(lefs[j] == 0) fins[j] = clock+1;
}
clock++;
return clock;
}
private int[] app(int[] a, int b)
{
int[] tmp = new int[a.length+1];
for(int i=0; i<a.length; i++) tmp[i] = a[i];
tmp[a.length] = b;
return tmp;
}
public String report()
{
String r = "JOB,PRIORITY,START,DURATION,FINISH,DELAY,PRI*DELAY\n";
float dn=0;
float pdn=0;
for(int i=0; i<stas.length; i++)
{
if(fins[i]>=0)
{
int delay = ((fins[i]-stas[i])-durs[i]);
r+= ""+i+","+pris[i]+","+stas[i]+","+durs[i]+","+fins[i]+","+delay+","+(pris[i]*delay)+"\n";
dn+= delay;
pdn+= pris[i]*delay;
}
else
{
int delay = ((clock*10-stas[i])-durs[i]);
r+= ""+i+","+pris[i]+","+stas[i]+","+durs[i]+","+fins[i]+","+delay+","+(pris[i]*delay)+"\n";
dn+= delay;
pdn+= pris[i]*delay;
}
}
if(stas.length>0)
{
r+= "Avg,,,,,"+(dn/stas.length)+","+pdn/stas.length+"\n";
}
return r;
}
public String toString()
{
String r = "There are "+stas.length+" jobs:\n";
for(int i=0; i<stas.length; i++)
{
r+= " JOB "+i+": START="+stas[i]+" DURATION="+durs[i]+" DURATION_LEFT="+lefs[i]+" PRIORITY="+pris[i]+"\n";
}
return r;
}
我不需要完整的代码,只需要了解如何存储等待时间并循环正确的作业。
最佳答案
虽然基于数组的解决方案“可能”有效,但我会提倡采用更加面向对象的方法。使用所需属性(id、start_time、wait 等)创建“Job”类。使用 csv 文件创建作业对象并将它们保存在列表中。编写一个比较器来对该作业列表进行排序(在本例中,基于作业等待/年龄将是因素)。
作业执行者必须执行以下操作:
while(jobs exist) {
iterate on the list {
if job is executable // start_time > current sys_time
consume cycles/job for executable jobs
mark completed jobs (optional)
}
remove the completed jobs
}
关于java - 循环调度程序,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32838119/