我试图借助子查询对查询进行排序,但总是得到一个
org.springframework.dao.InvalidDataAccessApiUsageException: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected AST node
例如
@Entity
@Table
public class Product extends AbstractEntity {
@OneToMany(mappedBy = "product")
private List<Item> items = new ArrayList<>();
}
@Entity
public class Item extends AbstractEntity {
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "product_id")
private Product product;
@Type(type = "org.jadira.usertype.dateandtime.joda.PersistentDateTime")
@Column(name = "delivery_date")
private DateTime deliveryDate;
}
我想查询所有产品,并按照该产品最早的交货日期对结果进行排序。我按如下方式构建查询:
CriteriaBuilder builder = manager.getCriteriaBuilder();
CriteriaQuery<Product> query = builder.createQuery(Product.class);
Root<Product> product = query.from(Product.class);
Subquery<DateTime> deliveryDateSQ = query.subquery(DateTime.class);
Root<Item> itemsFrom = deliveryDateSQ.from(Item.class);
deliveryDateSQ.select(
criteriaBuilder.least(itemsFrom.get(Item_.deliveryDate)));
deliveryDateSQ.where(
criteriaBuilder.equal(itemsFrom.get(Item_.product), product));
query.orderBy(criteriaBuilder.asc(deliveryDateSQ));
TypedQuery<Product> typedQuery = manager.createQuery(query);
执行查询时,我总是收到以下错误:
antlr.NoViableAltException: unexpected AST node: query
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.orderExpr(HqlSqlBaseWalker.java:1836) [hibernate-core-4.3.11.Final.jar:4.3.11.Final]
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.orderExprs(HqlSqlBaseWalker.java:1627) [hibernate-core-4.3.11.Final.jar:4.3.11.Final]
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.orderClause(HqlSqlBaseWalker.java:1603) [hibernate-core-4.3.11.Final.jar:4.3.11.Final]
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:642) [hibernate-core-4.3.11.Final.jar:4.3.11.Final]
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.selectStatement(HqlSqlBaseWalker.java:301) [hibernate-core-4.3.11.Final.jar:4.3.11.Final]
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:249) [hibernate-core-4.3.11.Final.jar:4.3.11.Final]
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:278) [hibernate-core-4.3.11.Final.jar:4.3.11.Final]
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:206) [hibernate-core-4.3.11.Final.jar:4.3.11.Final]
以及 Spring 的更多详细信息:
org.springframework.dao.InvalidDataAccessApiUsageException: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected AST node: query [...]
at org.springframework.orm.jpa.EntityManagerFactoryUtils.convertJpaAccessExceptionIfPossible(EntityManagerFactoryUtils.java:381)
at org.springframework.orm.jpa.vendor.HibernateJpaDialect.translateExceptionIfPossible(HibernateJpaDialect.java:216)
at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.translateExceptionIfPossible(AbstractEntityManagerFactoryBean.java:417)
at org.springframework.dao.support.ChainedPersistenceExceptionTranslator.translateExceptionIfPossible(ChainedPersistenceExceptionTranslator.java:59)
at org.springframework.dao.support.DataAccessUtils.translateIfNecessary(DataAccessUtils.java:213)
有没有办法以某种方式更改查询以使其按预期工作?
感谢您的帮助。
最佳答案
我们可以使用@OrderBy(clause = "delivery_date ASC") Hibernate 子句。
所以你的模型可以是这样的。
@Entity
@Table
public class Product extends AbstractEntity {
@OrderBy(clause = "delivery_date ASC")
@OneToMany(mappedBy = "product")
private List<Item> items = new ArrayList<>();
}
@Entity
public class Item extends AbstractEntity {
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "product_id")
private Product product;
@Type(type = "org.jadira.usertype.dateandtime.joda.PersistentDateTime")
@Column(name = "delivery_date")
private DateTime deliveryDate;
}
关于java - JPA 2.1 标准 API : Using subselects in orderBy,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33347498/