mysql - SQL - 匹配两行的条件

Question

我正在尝试从 SQL Developer 中提取符合两个行条件的数据。两行都有一个唯一值( ID )，表名是 abc.tcd

ID  =  Type =   GL code = amount
1   =   Debit =  0701  =  10000
1  =    credit = 0601 =   10000
1  =    Credit=  0501  =  1000
1   =   Debit=   0401   = 1000
2   =   Debit =  0701  =  9000
2   =   credit = 0801  =  9000
3   =   Debit  = 0701  =  6000
3   =   credit = 0601  =  6000

条件一:

GL code = '0701'   having Type = 'Debit' 

条件二:

GL code = '0601'   having Type = 'Credit' 

预期输出:

ID    Type    GL code  amount

1  =    Debit  = 0701 =   10000
1  =    credit = 0601 =   10000
1  =    Credit = 0501 =   1000
1  =    Debit  = 0401 =   1000
3  =    Debit  = 0701 =   6000
3  =    credit = 0601 =   6000

输出应该根据ID显示所有行

Answer 1

如果我对问题的理解正确，您想要提取所有 某些ID 的行，其中两个不同的行 满足两个不同的条件。您可以使用几个 in 运算符:

SELECT *
FROM   mytable
WHERE  id IN (SELECT id
              FROM   my_table
              WHERE  GLCode = '0701' AND Type = 'Debit')
        AND id IN (SELECT id
                   FROM   my_table
                   WHERE  GLCode = '0601' AND Type = 'Credit')

当然，这可以很容易地转换为使用 exists 运算符:

SELECT *
FROM   mytable a
WHERE  EXISTS (SELECT *
               FROM   my_table b
               WHERE  a.id = b.id AND b.GLCode = '0701' AND b.Type = 'Debit')
        AND EXISTS (SELECT *
                    FROM   my_table c
                    WHERE  a.id = c.id AND c.GLCode = '0601' AND c.Type = 'Credit')

一种更优雅的方法可能是使用 或 将所有条件包含在一个查询中，并 count 有多少条件被满足:

SELECT *
FROM   mytable
WHERE  id IN (SELECT   id
              FROM     my_table
              WHERE    (GLCode = '0701' AND Type = 'Debit') OR
                       (GLCode = '0601' AND Type = 'Credit')
              GROUP BY id
              HAVING   COUNT(*) = 2)