我有一个名为 tickets 的简单 MySQL 表
id | operator_id | product_id | created_timestamp
1 | STAFF001 | acc001 | 2015-01-01 22:00:00
2 | STAFF003 | acc004 | 2015-11-01 22:00:00
3 | STAFF002 | acc002 | 2015-01-01 22:00:00
4 | STAFF002 | acc003 | 2015-11-01 22:00:00
5 | STAFF001 | acc005 | 2015-01-01 22:00:00
6 | STAFF005 | acc002 | 2015-11-01 22:00:00
7 | STAFF004 | acc001 | 2015-01-01 22:00:00
8 | STAFF001 | acc001 | 2015-12-05 22:00:00
9 | STAFF003 | acc001 | 2015-01-01 22:00:00
10 | STAFF002 | acc007 | 2015-11-01 22:00:00
11 | STAFF001 | acc001 | 2015-12-03 22:00:00
12 | STAFF001 | acc001 | 2015-12-01 22:00:00
13 | STAFF005 | acc001 | 2015-01-01 22:00:00
14 | STAFF006 | acc001 | 2015-12-01 22:00:00
我应该如何编写 SQL 才能检索在彼此之间的 2 天之间创建的票证,这些票证也具有相同的 operator_id 和 product_id?
所以预期的结果是(忽略原因栏,它只是为了帮助解释)
id | operator_id | product_id | created_timestamp | reason
8 | STAFF001 | acc001 | 2015-12-05 22:00:00 | because it is within 2 days from id 11
11 | STAFF001 | acc001 | 2015-12-03 22:00:00 | because it is within 2 days from id 8 or 12
12 | STAFF001 | acc001 | 2015-12-01 22:00:00 | because it is within 2 days from id 11
这些不包括在内
id | operator_id | product_id | created_timestamp | reason
1 | STAFF001 | acc001 | 2015-01-01 22:00:00 | the date diff is too big
14 | STAFF006 | acc001 | 2015-12-01 22:00:00 | the date diff is ok for the same product_id (e.g. compared to id 11 and 8 )but the operator_id is different
many other ...
感谢您的帮助
最佳答案
select *
from tickets t1
join tickets t2 on
t1.id <> t2.id
and t1.operator_id = t2.operator_id
and t1.product_id = t2.product_id
and ABS(DATEDIFF(t1.created_timestamp, t2.created_timestamp)) <= 2
;
我添加了 ABS() 函数,因为您有以下记录:
第一张日期为 2015-12-05 且 ID 为 8 的票
日期为 2015-12-03 且 ID 为 11 的第二张票
关于MySQL在某些日期之间找到重复的行,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28978984/