我想知道是否可以将此标准转换为独立的标准。我没有正确理解独立的标准。有人可以帮忙吗?
Criteria crit = sessionC.createCriteria(OP_DOCTOR_VISIT.class, "OPDV1");
crit.createAlias("OPDV1.OP_VISIT", "OPDV2", JoinType.LEFT_OUTER_JOIN, Restrictions.and(Restrictions.eq("OPDV2.FORM", "NEW"), Restrictions.ge("OPDV2.USER_DATETIME", fromdate), Restrictions.le("OPDV2.USER_DATETIME", todate)));
crit.add(Restrictions.ge("OPDV1.USER_DATETIME", fromdate));
crit.add(Restrictions.le("OPDV1.USER_DATETIME", todate));
ProjectionList p1 = Projections.projectionList();
p1.add(Projections.alias(Projections.count("OPDV1.OP_VISIT_ID"), "TOTAL"));
p1.add(Projections.count("OPDV2.FORM"));
p1.add(Projections.alias(Projections.sqlGroupProjection("date(this_.USER_DATETIME) as createdDate", "createdDate", new String[]{"createdDate"}, new Type[]{StandardBasicTypes.DATE}), "DAT"));
crit.setProjection(p1);
是否可以重写上面的内容,以便我可以避免在下面给出的 POJO 中使用“@OneToMany”。
POJO
@Entity
@Table(name = "OP_DOCTOR_VISIT")
@SQLDelete(sql = "UPDATE OP_DOCTOR_VISIT SET DELETED = 'DELETED' WHERE OP_VISIT_ID = ? and VERSION_UPDATES = ?")
@Where(clause = "DELETED <> 'DELETED'")
public class OP_DOCTOR_VISIT implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "OP_VISIT_ID")
private Long OP_VISIT_ID;
@OneToMany(mappedBy = "OP_VISIT_ID", cascade = CascadeType.ALL, fetch = FetchType.LAZY)
@LazyCollection(LazyCollectionOption.EXTRA)
@Fetch(FetchMode.SELECT)
private List<OP_DOCTOR_VISIT> OP_VISIT;
public Long getOP_VISIT_ID() {
return OP_VISIT_ID;
}
public void setOP_VISIT_ID(Long OP_VISIT_ID) {
this.OP_VISIT_ID = OP_VISIT_ID;
}
public List<OP_DOCTOR_VISIT> getOP_VISIT() {
return OP_VISIT;
}
public void setOP_VISIT(List<OP_DOCTOR_VISIT> OP_VISIT) {
this.OP_VISIT = OP_VISIT;
}
}
最佳答案
仅限您创建条件对象的第一行。
DetachedCriteria
允许您在没有 session 的情况下创建查询。因此,您在构建查询时不需要 session 。DetachedCriteria
与 Criteria 相同,只是您可以在没有 session 的情况下创建查询。DetachedCriteria detachedCriteria = DetachedCriteria.forClass(OP_DOCTOR_VISIT.class);
最后,当 session 对象可用时,您可以执行查询
`criteria.getExecutableCriteria(session)。
关于java - 将条件转换为自连接的独立条件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35424717/